Chapter 14, Problem 14.96SP

Interpretation Introduction

Interpretation:

The activation energy of the reaction if the rate of the reaction is increased by a factor of 15 on raising the temperature from $25°\text{C}$ to $50°\text{C}$ needs to be determined.

Concept introduction:

The Arrhenius equation is applied to calculate activation energy.

$\ln \frac{K_2}{K_1}=\frac{E_a}{R}\left[\frac{1}{T_1}-\frac{1}{T_2}\right]$

Where $K_2$ and $K_1$ are rate constant, $E_a$ is activation energy, R is gas constant, $T_1\text{and}{T}_2$ are initial and finale temperatures respectively.