Chapter 14, Problem 14.74SP

Interpretation Introduction

(a)

Interpretation:

The molarity of butadiene needs to be determined.

Concept introduction:

Integrated rate law for the second-order reaction is as follows:

$\frac{\text{1}}{{\left[\text{A}\right]}_t}-\frac{\text{1}}{{\left[\text{A}\right]}_{°}}=k\text{t}$

Here, ${\left[\text{A}\right]}_0$ is initial concentration, ${\left[\text{A}\right]}_t$ is concentration after time t and k is rate constant.

If we plot $\frac{\text{1}}{\left[\text{A}\right]}$ against t then it will be a straight line. The slope of the graph is $\text{k}$.

Fig-1

Interpretation Introduction

(b)

Interpretation:

The time in hours needs to be determined.

Concept introduction:

Integrated rate law for the second-order reaction is as follows:

$\frac{\text{1}}{{\left[\text{A}\right]}_t}-\frac{\text{1}}{{\left[\text{A}\right]}_{°}}=k\text{t}$

Here, ${\left[\text{A}\right]}_0$ is initial concentration, ${\left[\text{A}\right]}_t$ is concentration after time t and k is rate constant.