Organic Chemistry: Principles and Mechanisms (Second Edition)
Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Chapter 14, Problem 14.51P
Interpretation Introduction

Interpretation:

Which portion of doxorubicin intercalates into DNA and why it has little difficulty doing so, is to be explained.

Concept introduction:

The nitrogenous bases form hydrogen bonds between opposing DNA strands to form the double helix of DNA found in the nucleotides. The four nitrogenous bases found in DNA are guanine (G), adenine (A), cytosine (C), and thymine (T)., Guanine is always paired with cytosine, and Adenine is always paired with thymine. These are recognized as base pairs.

Each of these ring systems is aromatic, consists of atoms that have planar geometries, and are sp2 hybridized. The aromaticity of nitrogenous bases is advantageous. First, it allows each base pair to be planar and to maximize the overlap of the p orbitals that make up the π system of MOs. The hydrogen bonding essentially locks complementary bases in the same plane. DNA base pairs are “stacked” on the inside of DNA. The second advantage of aromaticity of base pairs is it provides stability to the DNA double helix. Because nitrogenous bases are stacked on top of one another, p AOs from the aromatic system of one nitrogenous base overlaps with p AOs from another nitrogenous base attached to an adjacent sugar. This is a stabilizing interaction called π stacking.

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(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³
fcrip = ↓ bandwidth Il temp 32. What impact (increase, decrease, or no change) does each of the following conditions have on the individual components of the van Deemter equation and consequently, band broadening? Increase temperature Longer column Using a gas mobile phase instead of liquid Smaller particle stationary phase Multiple Paths Diffusion Mass Transfer
34. Figure 3 shows Van Deemter plots for a solute molecule using different column inner diameters (i.d.). A) Predict whether decreasing the column inner diameters increase or decrease bandwidth. B) Predict which van Deemter equation coefficient (A, B, or C) has the greatest effect on increasing or decreasing bandwidth as a function of i.d. and justify your answer. Figure 3 Van Deemter plots for hydroquinone using different column inner diameters (i.d. in μm). The data was obtained from liquid chromatography experiments using fused-silica capillary columns packed with 1.0-μm particles. 35 20 H(um) 큰 20 15 90 0+ 1500 100 75 550 01 02 594 05 μ(cm/sec) 30 15 10

Chapter 14 Solutions

Organic Chemistry: Principles and Mechanisms (Second Edition)

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