Concept explainers
(a)
Interpretation:
Whether the given molecule is
Concept introduction:
The molecules, to be aromatic, must obey Hückel’s rule of
Answer to Problem 14.41P
The given molecule is nonaromatic due to lack of planarity.
Explanation of Solution
The given structure is:
The molecule has total
The molecule is determined as nonaromatic based on the structure planarity.
(b)
Interpretation:
Whether the given molecule is aromatic, antiaromatic, or nonaromatic, is to be determined.
Concept introduction:
The molecules, to be an aromatic, must obey Hückel’s rule of
Answer to Problem 14.41P
The given molecule is nonaromatic due to lack of planarity.
Explanation of Solution
The given structure is:
The molecule has total
The molecule is determined as nonaromatic based on the structure planarity.
(c)
Interpretation:
Whether the given molecule is aromatic, antiaromatic, or nonaromatic, is to be determined.
Concept introduction:
The molecules, to be an aromatic, must obey Hückel’s rule of
Answer to Problem 14.41P
The given molecule is aromatic as it is planar, has cyclic conjugation, and obeys Hückel’s rule.
Explanation of Solution
The given structure is:
The given molecule is planar and has total
The molecule is determined as aromatic based on the Hückel’s rule.
(d)
Interpretation:
Whether the given molecule is aromatic, antiaromatic, or nonaromatic, is to be determined.
Concept introduction:
The molecules, to be an aromatic, must obey Hückel’s rule of
Answer to Problem 14.41P
The given molecule is nonaromatic due non cyclic conjugated system.
Explanation of Solution
The given structure is:
The molecule has a conjugated system of total
The molecule is determined as nonaromatic based on the non cyclic structure which lacks cyclic conjugation.
(e)
Interpretation:
Whether the given molecule is aromatic, antiaromatic, or nonaromatic, is to be determined.
Concept introduction:
The molecules, to be an aromatic, must obey Hückel’s rule of
Answer to Problem 14.41P
The given molecule is aromatic as it is planar, has cyclic conjugation, and obeys Hückel’s rule.
Explanation of Solution
The given structure is:
The molecule is planar and has fully cyclic conjugated system of total
The molecule is determined as aromatic based on planarity, fully conjugated system, and having Hückel’s rule of
(f)
Interpretation:
Whether the given molecule is aromatic, antiaromatic, or nonaromatic, is to be determined.
Concept introduction:
The molecules, to be an aromatic, must obey Hückel’s rule of
Answer to Problem 14.41P
The given molecule is nonaromatic as it is not conjugated and does not obey Hückel’s rule.
Explanation of Solution
The given structure is:
The molecule has only
The molecule is determined as nonaromatic based on the non-conjugated system of
(g)
Interpretation:
Whether the given molecule is aromatic, antiaromatic, or nonaromatic, is to be determined.
Concept introduction:
The molecules, to be an aromatic, must obey Hückel’s rule of
Answer to Problem 14.41P
The given molecule is nonaromatic as it has no cyclic conjugated system.
Explanation of Solution
The given structure is:
One of the lone pair on the oxygen atom participates in the resonance, thus, the molecule has
The molecule is determined as nonaromatic based on non-conjugated system of
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Chapter 14 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- Complete boxes in the flow chart. Draw the structure of the organic compound foundin each layer after adding 3M NaOH and extraction. Make sure to include any charges. Provide explanation on answers.arrow_forward== Vid4Q2 Unanswered ☑ Provide IUPAC name of product in the reaction below A 3,4-dimethylcyclohexene B 1,2-dimethylcyclohexane C 1,2-dimethylcyclohexene D 3,4-dimethylcyclohexane H₂ Pdarrow_forward5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.arrow_forward
- Nonearrow_forwardStereochemistry: Three possible answers- diastereomers, enantiomers OH CH₂OH I -c=0 21108 1101 41745 HOR CH₂OH IL Но CH₂OH TIL a. Compounds I and III have this relationship with each other: enantiomers b. Compounds II and IV have this relationship with each other: c. Compounds I and II have this relationship with each other: d. *Draw one structure that is a stereoisomer of II, but neither a diastereomer nor an enantiomer. (more than one correct answer)arrow_forwardNonearrow_forward
- Don't used Ai solutionarrow_forwardIn mass spectrometry, alpha cleavages are common in molecules with heteroatoms. Draw the two daughter ions that would be observed in the mass spectrum resulting from an alpha cleavage of this molecule. + NH2 Q Draw Fragment with m/z of 72arrow_forwardDon't used Ai solution and don't used hand raitingarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning