Concept explainers
Interpretation:
The complete MO picture and energy diagram for the allyl anion
Concept introduction:
The overlap of the two atomic orbitals (AOs) results in the formation of two molecular orbitals (MOs). One of these, called the bonding MO, is formed as a result of constructive interaction. It is lower in energy than the original AOs. The other, called the antibonding MO, is formed as a result of destructive interaction. It is higher in energy than the original AOs. Antibonding MOs have a node (a nodal plane) situated between the two atoms. The overall character of the MO is determined by the number of bonding and antibonding interactions between the AOs. If the bonding interactions are more, the overall character is bonding. If the antibonding interactions are more, the overall character is antibonding. If they are equal or there are none, the MO is nonbonding.
Depending on whether the AOs overlap along the bond axis or away from the bond axis (sideways), the MOs are designated as
In a molecule with double bonds, all bonding
For a linear system of conjugated p orbitals, all nodal planes in a resulting
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EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
- Consider the following orbital representation of HCCH (ethyne). a. Answer the same three questions (a-c) from the previous exercise. b. Label each CH bond in the drawing above. c. What is the total number of a bonds found in ethyne?…. bonds? d. How many p orbitals are there on a single carbon of ethyne? e. How many hybrid orbitals are there on a single carbon of ethyne?arrow_forward! ( answer with step by step explanation)arrow_forwardPlace the following in order of decreasing dipole moment. |- CH4 II - CH3OH III - CH3SH III > | > || Il > | > II | > II| > | || > III > I | = II| > ||arrow_forward
- Don't use ai to answer I will report your answer Solve it Asap with explanation of all parts why correct/incorrect.arrow_forwardHandwritten solutions are strictly prohibitedarrow_forwardPlace the following in order of increasing dipole moment. |- HI Il - HF III - HCI |< || = |II Il < III < | | < || < |II O Il < I < II OI< III < |arrow_forward
- Problem is attached! Need help, Stuck! Please and thank you!arrow_forward5. Which one of the following structures represents the resonance contributor of a molecule in the box in agreement with the shown curved arrows? A) H,N=N=N: B) H,N-N=N: H,NN C) H,N=N=N: D) H,N=N=N: OA OB OD Question 6 6. Which orbitals overlap to form the carbon-oxygen sigma-bond of acetaldehyde, CH;CHO ? O sp+ sp O sp+ sp O sp+ sp O spt sparrow_forwardWhich drawing best represents the resonance hybrid for the given molecule? HH H&H Give correct detailed Solution with explanation needed. don't give Handwritten answer O 8 8 H ད དག་ ་arrow_forward
- Re-sketch the diazene molecule and label all bond dipoles (with the arrow pointing from the most electronegative atom to the least electronegative atom). Show using vector sums that this geometric isomer of diazene is non-polar.arrow_forwardit won't let me do OH togetherarrow_forwarductrawned option 1-4 to describe the hybridization of the following ions. Он 01. ghighted carbocatiIons and carbanion show sp hybridization. 02 Highlighted carbocations and carbanion show sp2 hybridization. 03 Highlighted carbocations and carbanion show sp3 hybridization. 04 Highlighted carbanion shows sp hybridization and cations show sp2 hybridization. oving to another question will save thearrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning