Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 14, Problem 13RQ
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Why do you have to be careful when using analogies?
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Chapter 14 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 14 - How does the darkness of the night sky tell you...Ch. 14 - How can Earth be located at the center of the...Ch. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Why couldn’t atomic nuclei exist when the e of the...Ch. 14 - Why are measurements of the present density of the...Ch. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - What is the evidence that the Universe was very...Ch. 14 - Prob. 10RQ
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- 1. The current (critical) density of our universe is pe = 10-26kg/m³. Assume the universe is filled with cubes with equal size that each contain one person of m = 100kg. What would the length of the side of such a cube have to be in order to give the correct critical density? How many hydrogen atoms would you need in a box of 1 m³ to reach the critical density? The matter we know, which consists mostly of hydrogen, constitutes only 4.8% of the current critical energy density of our universe. So how many hydrogen atoms are actually in a box of 1 m3 in our universe? Deep space is very empty and a much better vacuum than we can obtain on earth in a laboratory.arrow_forwardIt is possible to derive the age of the universe given the value of the Hubble constant and the distance to a galaxy, again with the assumption that the value of the Hubble constant has not changed since the Big Bang. Consider a galaxy at a distance of 400 million light-years receding from us at a velocity, v. If the Hubble constant is 20 km/s per million light-years, what is its velocity? How long ago was that galaxy right next door to our own Galaxy if it has always been receding at its present rate? Express your answer in years. Since the universe began when all galaxies were very close together, this number is a rough estimate for the age of the universe.arrow_forwardExplain the Higher-Order Systems?arrow_forward
- An astronomer observed the motions of some galaxies. Based on his observations, he made the following statements. Which one of them is most likely to be false? Take Hubble's constant to be 67 km/s/Mpc. A. A galaxy observed to be moving away from us at a speed of 70 km/s is at a distance of about 1 Mpc from us. B. A galaxy observed to be moving away from us at a speed of 700 km/s is at a distance of about 10 Mpc from us. C. A galaxy observed to be moving away from us at a speed of 7000 km/s is at a distance of about 100 Mpc from us. D. A galaxy observed to be moving away from us at a speed of 70000 km/s is at a distance of about 1 Gpc from us. Is the answer D? Thank you!arrow_forwardplease solve the question step by step so I can understand better. Thank youarrow_forwardHow did they get 0 and then 1250nm for the answers? Trying to study for a quiz can you guys help pleasearrow_forward
- Are the galaxies red-shifting or blue-shifting? Explain. (You may find the big-bang theory helpful). Andromeda galaxy is currently approaching our galaxy with a radial velocity of 266 km/sec. How far is our galaxy from Andromeda? (Hubble’s constant, H, is 73 km/sec/MParsec). When can the two galaxies be anticipated to collide?arrow_forwardHello. I need help solving ( 9 & 10) with explanations, it goes with the diagram above. Please and thank you.arrow_forwardThe Andromeda Galaxy, M31, is the closest large spiral galaxy to our Milky Way. When we look at its chemical spectrum, we see that its hydrogen alpha emission line (Hα) has an observed wavelength of λobs = 655 nm.-Calculate z, being careful with the sign.-How fast is it moving in km/s?-Is it redshifted or blueshifted? Is it moving towards or away from us? answer to three significant figures.arrow_forward
- Hi. I still don't get it. I'm not sure what sin and cos have to do with it. But either way, I'm still stuck in the same place. I don't know how you got from steps 3 and 4 to the next step. One is for the x-axis and the other for the y-axis. How did they end up merged together? If you apply the Pythagorean theorem, you get either:v = sqrt{(vcos) 2 + (vsin) 2} Then what? Or you get:v = sqrt{(m1v1/m1+m2)2 + (m2v2/m1+m2)2} Now what? That "adding" step just looks like the Pythagorean theorem, with v2 being the c in c2 = a2 + b2, but what is going on on the other side of the equation? I don't understand how in the denominator you went from:(m1 + m2)2 + (m1 + m2)2 to(m1 + m2)2It seems to me like (m1 + m2)2 + (m1 + m2)2 = 2(m1 + m2)2 Explain as if I didn't understand the algebra, because I think that's the issue here.arrow_forwardHello, here is the answer given by another expert. Seems to be different from your answer. . . Could you please double check the answer? Thank you so much. this answer is very important to mearrow_forwardThe Andromeda Galaxy is a member of the Local Group of galaxies. It is approaching us. Does this mean that the Hubble Law is wrong? Why or why not? Explain.arrow_forward
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