
Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Textbook Question
Chapter 14, Problem 2RQ
How can Earth be located at the center of the observable Universe if you accept the cosmological principle?
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36. Example 5.7: You whirl a bucket of water around in a vertical
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Passage Problems
Laptop computers are equipped with accelerometers that sense when
the device is dropped and then put the hard drive into a protective mode.
Your computer geek friend has written a program that reads the accel-
erometer and calculates the laptop's apparent weight. You're amusing
yourself with this program on a long plane flight. Your laptop weighs
just 5 pounds, and for a long time that's what the program reports. But
then the "Fasten Seatbelt" light comes on as the plane encounters turbu-
lence. Figure 4.27 shows the readings for the laptop's apparent weight
over a 12-second interval that includes the start of the turbulence.
76. At the first sign of turbulence,
the plane's acceleration
a. is upward.
b. is downward.
c. is impossible to tell from
the graph.
77. The plane's vertical ac-
celeration has its greatest
magnitude
a. during interval B.
b. during interval C.
c. during interval D.
78. During interval C, you can
conclude for certain that the
plane is
Apparent…
If the metal sphere on the Van de Graff has a charge of 0.14 Coulombs and the person has a mass of 62 kg, how much excess charge would the person need in order to levitate at a distance 25 cm from the center of the charged metal sphere? Assume you can treat both the person and the metal sphere as point charges a distance 25 cm from each other
Chapter 14 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 14 - How does the darkness of the night sky tell you...Ch. 14 - How can Earth be located at the center of the...Ch. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Why couldn’t atomic nuclei exist when the e of the...Ch. 14 - Why are measurements of the present density of the...Ch. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - What is the evidence that the Universe was very...Ch. 14 - Prob. 10RQ
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- If the metal sphere on the Van de Graff has a charge of 0.14 Coulombs and the person has a mass of 62 kg, how much excess charge would the person need in order to levitate at a distance 25 cm from the center of the charged metal sphere? Assume you can treat both the person and the metal sphere as point charges a distance 25 cm from each other (so that you can use Coulomb's Law to calculate the electrical force).arrow_forwardUsing Coulomb's Law, calculate the magnitude of the electrical force between two protons located 1 meter apart from each other. (Give your answer as the number of Newtons but as usual you only need to include the number, not the unit label.)arrow_forwardPart A You want to get an idea of the magnitude of magnetic fields produced by overhead power lines. You estimate that a transmission wire is about 12 m above the ground. The local power company tells you that the line operates at 12 kV and provide a maximum of 60 MW to the local area. Estimate the maximum magnetic field you might experience walking under such a power line, and compare to the Earth's field. [For an ac current, values are rms, and the magnetic field will be changing.] Express your answer using two significant figures. ΟΤΕ ΑΣΦ VAΣ Bmax= Submit Request Answer Part B Compare to the Earth's field of 5.0 x 10-5 T. Express your answer using two significant figures. Ο ΑΣΦ B BEarth ? ? Tarrow_forward
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- 64. Two springs have the same unstretched length but different spring constants, k₁ and k₂. (a) If they're connected side by side and stretched a distance x, as shown in Fig. 4.24a, show that the force exerted by the combination is (k₁ + k₂)x. (b) If they're con- nected end to end (Fig. 4.24b) and the combination is stretched a distance x, show that they exert a force k₁k2x/(k₁ + k₂). www (a) FIGURE 4.24 Problem 65 www (b)arrow_forward65. Although we usually write Newton's second law for one-dimensional motion in the form F =ma, which holds when mass is constant, d(mv) a more fundamental version is F = . Consider an object dt whose mass is changing, and use the product rule for derivatives to show that Newton's law then takes the form F dm = ma + v dtarrow_forwardIf a proton is located on the x-axis in some coordinate system at x0 = -3.2 x 10-5 meters, what is the x-component of the Electric Field due to this proton at a position x = +3.2 x 10-5 meters and on the x axis as the y-axis is 0 giving a number of Newtons/Coulomb?arrow_forward
- Consider a single square loop of wire of area A carrying a current I in a uniform magnetic field of strength B. The field is pointing directly up the page in the plane of the page. The loop is oriented so that the plane of the loop is perpendicular to the plane of the page (this means that the normal vector for the loop is always in the plane of the page!). In the illustrations below the magnetic field is shown in red and the current through the current loop is shown in blue. The loop starts out in orientation (i) and rotates clockwise, through orientations (ii) through (viii) before returning to (i). (i) Ø I N - - I N - (iii) (iv) (v) (vii) (viii) a) [3 points] For each of the eight configurations, draw in the magnetic dipole moment vector μ of the current loop and indicate whether the torque on the dipole due to the magnetic field is clockwise (CW), counterclockwise (CCW), or zero. In which two orientations will the loop experience the maximum magnitude of torque? [Hint: Use the…arrow_forwardPlease help with calculating the impusle, thanks! Having calculated the impact and rebound velocities of the ping pong ball and the tennis ball calculate the rebounding impulse: 1.Measure the weight of the balls and determine their mass. Tennis ball: 0.57 kg Ping Pong Ball: 0.00246 kg The impulse, I, is equal to the change in momentum, Pf-Pi. Note the sign change, i.e., going down is negative and up is positive. The unit for momentum is kg-m/s. The change is momentum, impulse, is often givens the equivalent unit of N-S, Newton-Secondarrow_forward5. Three blocks, each with mass m, are connected by strings and are pulled to the right along the surface of a frictionless table with a constant force of magnitude F. The tensions in the strings connecting the masses are T1 and T2 as shown. m T1 T2 F m m How does the magnitude of tension T₁ compare to F? A) T₁ = F B) T₁ = (1/2)F C) T₁ = (1/3)F D) T₁ = 2F E) T₁ = 3Farrow_forward
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