Chapter 14, Problem 111APP

Interpretation Introduction

Interpretation: The ${\text{[OH}}^{\text{-}}\text{]}$ should be determined in a solution that contains $\text{0}\text{.225 g NaOH}$ in $\text{0}\text{.250 L}$ of solution.

Concept Introduction: The ratio of number of moles of solute, $\text{n}$ to the volume of solution in liters, $\text{V}$ is said to be the molarity, $\text{M}$ . It is to expressed as:

  $\text{M = }\frac{\text{n}}{\text{V(in L)}}$