Chapter 14, Problem 10SAQ

Interpretation Introduction

Interpretation:

To find outthe rate constant at 50.0°C.

Concept Introduction:

The Arrhenius Equation is given as:

k=Ae^−E_a/RT

where, k is rate constant, A is collision frequency factor, E_a is the activation energy, R is gas constant and T is temperature in Kelvin.

For two different rate constants and different temperatures, the equation is:

$\text{In}\frac{{\text{k}}_{\text{2}}}{{\text{k}}_{\text{1}}}\text{=-}\frac{{\text{E}}_{\text{a}}}{\text{R}}\left(\frac{\text{1}}{{\text{T}}_{\text{1}}}\text{-}\frac{\text{1}}{{\text{T}}_{\text{2}}}\right)$