The major component of products formed in the given reaction is to be identified. Concept introduction: In the presence of Lewis acid, benzene reacts with alkyl halide , undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation. The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

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Answer 1

Question

Chapter 13.6, Problem 6P

Interpretation Introduction

Interpretation:

The major component of products formed in the given reaction is to be identified.

Concept introduction:

In the presence of Lewis acid, benzene reacts with alkyl halide, undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation.

The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

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Answer 2

Question

Chapter 13.6, Problem 6P

Interpretation Introduction

Interpretation:

The major component of products formed in the given reaction is to be identified.

Concept introduction:

In the presence of Lewis acid, benzene reacts with alkyl halide, undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation.

The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

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Answer 3

Question

Chapter 13.6, Problem 6P

Interpretation Introduction

Interpretation:

The major component of products formed in the given reaction is to be identified.

Concept introduction:

In the presence of Lewis acid, benzene reacts with alkyl halide, undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation.

The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

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Answer 4

Question

Chapter 13.6, Problem 6P

Interpretation Introduction

Interpretation:

The major component of products formed in the given reaction is to be identified.

Concept introduction:

In the presence of Lewis acid, benzene reacts with alkyl halide, undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation.

The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

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Answer 5

Chapter 13.6, Problem 6P

Interpretation Introduction

Interpretation:

The major component of products formed in the given reaction is to be identified.

Concept introduction:

In the presence of Lewis acid, benzene reacts with alkyl halide, undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation.

The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

Answer 6

Chapter 13.6, Problem 6P

Interpretation Introduction

Interpretation:

The major component of products formed in the given reaction is to be identified.

Concept introduction:

In the presence of Lewis acid, benzene reacts with alkyl halide, undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation.

The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

Answer 7

Chapter 13.6, Problem 6P

Interpretation Introduction

Interpretation:

The major component of products formed in the given reaction is to be identified.

Concept introduction:

In the presence of Lewis acid, benzene reacts with alkyl halide, undergoes alkylation and forms alkylbenzene. This is called Friedel–Crafts alkylation.

The Friedel–Crafts alkylation reaction occurs through the formation of carbocation. Thus, the primary alkyl halide undergoes rearrangement by hydride shift to form a more stable carbocation.

Answer 8

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Answer 11

Ch. 13.2 - Based on Hammonds postulate which holds that the...Ch. 13.3 - Prob. 2P Ch. 13.3 - Using : O =N+= O : as the electrophile, write a...Ch. 13.4 - Prob. 4P Ch. 13.5 - Prob. 5P Ch. 13.6 - Prob. 6P Ch. 13.6 - Write a reasonable mechanism for the formation of...Ch. 13.6 - tert-Butylbenzene can be prepared by alkylation of...Ch. 13.6 - Prob. 9P Ch. 13.7 - The reaction shown gives a single product in 88...

Solution Summary: The author explains the mechanism of alkylation of benzene with 1-chloropropane aluminum chloride.

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Chapter 13 Solutions

Solution Summary: The author explains the mechanism of alkylation of benzene with 1-chloropropane&#160;aluminum chloride.

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Chapter 13 Solutions

Solution Summary: The author explains the mechanism of alkylation of benzene with 1-chloropropane aluminum chloride.