Campbell Biology, Books a la Carte Edition (11th Edition)
Campbell Biology, Books a la Carte Edition (11th Edition)
11th Edition
ISBN: 9780134154121
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece
Publisher: PEARSON
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Chapter 13.4, Problem 3CC
Summary Introduction

To explain: The possibility of genetic variation if crossing over is between paternal and maternal chromatids having the exactly similar alleles for every gene.

Concept introduction:

Crossing over is the process of exchange of gene segments among non-sister homologous chromatids. It forms recombinant chromosomes that contain genetic materials from both parents that generate genetic variation.

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Anwser these Discussion Questions: Part One Why were the plants kept in the dark prior to the experiment? Why is this important? Why is it important to boil the leaf? Explain why it was necessary to use boiling alcohol? What is the purpose of the iodine? Part Two What was the purpose of keeping the leaf in the dark and then covering it with a cardboard cut-out? What conclusions can you draw from this part of the lab? Part Three 7. In this experiment what was the purpose of adding the soda lime? 8. Why was a sealed bag placed around each plant? 9. What happened in the control plants? 10. What was the result on photosynthesis? Part Four 11. Why was a variegated leaf used in this experiment? !2. What conclusions can you draw about starch production in a variegated leaf?
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series of two-point crosses were carried out among six loci (a, b, c, d, e and f), producing the following recombination frequencies. According to the data below, the genes can be placed into how many different linkage groups? Loci a and b Percent Recombination 50 a and c 14 a and d 10 a and e 50 a and f 50 b and c 50 b and d 50 b and e 35 b and f 20 c and d 5 c and e 50 c and f 50 d and e 50 d and f 50 18 e and f Selected Answer: n6 Draw genetic maps for the linkage groups for the data in question #5. Please use the format given below to indicate the genetic distances. Z e.g. Linkage group 1=P____5 mu__Q____12 mu R 38 mu 5 Linkage group 2-X_____3 mu__Y_4 mu sanight
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