Explanation Given information: There are two Grass seeds. Grass seed A is worth $ 2.50 per pound and seed B is worth $ 1.75 per pound. Formula used: There are the steps to be used for translating this problem. Step1: Familiarize. First the variable to the quantity which is to be calculated. Step2: Translate. Now the provided problem into an equation using variable. Step3: Solve. Solve both the equations of two variable using substitution method. Step4: Check. Put the solutions obtained in the original equation. Calculation: Familiarize: Consider x is the pounds of Grass seeds A and y is the pounds of Grass seeds B. Arranging the information in a table, Grass seed A Grass seed B Mixture Equation Cost per pound $ 2.50 $ 1.75 $ 2.14 Amount (in pounds) x y 75 x + y = 75 Total mixture 2.50 x 1.75 y 2.14 × 75 = 160.5 2.50 x + 1.75 y = 160.5 From the second row of the table, Total cost of mixture: x + y = 75 …… ( 1 ) The cost of Grass seed A is 2.50 x , cost of Grass seed B is 1.75 y and the cost of mixture is 160.5 . Total mixture: 2.50 x + 1.75 y = 160.5 …… ( 2 ) By using elimination method to solved the given equation (1) and equation (2). Now Multiply by − 2.50 on both side of equation ( 1 ) x + y = 75 , − 2.50 x − 2.50 y = − 187.5 Add this new equation − 2.50 x − 2.50 y = − 187

9th Edition

ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Chapter 13.4, Problem 20ES

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To calculate: The number of pounds of Grass seed use in order to make 75lb of mixture worth $2.14 pounds when seed A is worth $2.50 per pound and seed B is worth $1.75 per pound.

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Chapter 13.4, Problem 19ES

Chapter 13.4, Problem 21ES

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Chapter 13 Solutions

Developmental Mathematics (9th Edition)

Ch. 13.1 - Prob. 1SR Ch. 13.1 - Prob. 2SR Ch. 13.1 - Prob. 1DE Ch. 13.1 - Prob. 2DE Ch. 13.1 - Prob. 3DE Ch. 13.1 - Prob. 4DE Ch. 13.1 - Prob. 5DE Ch. 13.1 - Prob. 6DE Ch. 13.1 - Prob. 7DE Ch. 13.1 - Prob. 8DE

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The number of pounds of Grass seed use in order to make 75lb of mixture worth $ 2.14 pounds when seed A is worth $ 2.50 per pound and seed B is worth $ 1.75 per pound.

Solution Summary: The author calculates the number of pounds of Grass seed used to make 75lb of mixture worth 2.14

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To calculate: The number of pounds of Grass seed use in order to make 75lb of mixture worth $2.14 pounds when seed A is worth $2.50 per pound and seed B is worth $1.75 per pound.

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Chapter 13 Solutions