Explanation Given Information: The provided equations are, x − y = 6 x + y = − 2 Formula used: Multiplication property of equality: A = B and A ⋅ C = B ⋅ C are equivalent where C ≠ 0 . If A , B and C are real numbers then, Addition property of equality: A = B and A + C = B + C are equivalent. Calculation: Consider the system of equations: x − y = 6 …… (1) x + y = − 2 …… (2) Since, coefficient of x is 1 in the equation ( 1 ) Thus, Use addition property, Add ( y ) to both sides of the equation ( 1 ) Thus, x − y + y = 6 + y x = 6 + y Put the value x = 6 + y in equation ( 2 ) Thus, 6 + y + y = − 2 Take like terms together, 6 + 2 y = − 2 Use addition property, Add ( − 6 ) to both sides, 6 + 2 y − 6 = − 2 − 6 2 y = − 8 Use multiplication property, Multiply both side by ( 1 2 )

9th Edition

ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Chapter 13.2, Problem 13ES

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To calculate: The solution of equation x−y=6, x+y=−2 using substitution method. Solve first one equation for one variable..

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Chapter 13.2, Problem 12ES

Chapter 13.2, Problem 14ES

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Chapter 13 Solutions

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Ch. 13.1 - Prob. 1SR Ch. 13.1 - Prob. 2SR Ch. 13.1 - Prob. 1DE Ch. 13.1 - Prob. 2DE Ch. 13.1 - Prob. 3DE Ch. 13.1 - Prob. 4DE Ch. 13.1 - Prob. 5DE Ch. 13.1 - Prob. 6DE Ch. 13.1 - Prob. 7DE Ch. 13.1 - Prob. 8DE

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The solution of equation x − y = 6 , x + y = − 2 using substitution method. Solve first one equation for one variable..

Solution Summary: The author calculates the solution of the equation x-y=6,x+y =-2 using substitution method.

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To calculate: The solution of equation x−y=6, x+y=−2 using substitution method. Solve first one equation for one variable..

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Chapter 13 Solutions