Explanation Given Information: The perimeter of the two-by –four pieces of lumber is 10 in and length is 2 in more than the width. Formula used: Perimeter of rectangle is, 2 l + 2 w , where l, w represents the length and width of rectangle respectively. Multiplication property of equality: A = B and A ⋅ C = B ⋅ C are equivalent where C ≠ 0 . If A , B and C are real numbers then, Addition property of equality: A = B and A + C = B + C are equivalent. Calculation: Consider the Provided information, Perimeter of the two-by four pieces of lumber is 10 in And length is 2 in more than the width. According to the question, 2 l + 2 w = 10 And l = 2 + w Thus, we have following system of equations, 2 l + 2 w = 10 …… (1) l = 2 + w …… (2) Put the value l = 2 + w in equation ( 1 ) Thus, 2 ( 2 + w ) + 2 w = 10 Remove parentheses, 4 + 2 w + 2 w = 10 Take like terms together, 4 + 4 w = 10 Use addition property, Add ( − 4 ) to both sides, 4 + 4 w − 4 = 10 − 4 4 w = 6 Use multiplication property, Multiply both side by ( 1 4 )

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ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Chapter 13.2, Problem 25ES

To determine

To calculate: The actual dimensions of a cross section of a two-by-four piece of lumber if the

the perimeter is 10 in and the length is 2 in more than the width.

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Chapter 13.2, Problem 24ES

Chapter 13.2, Problem 26ES

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Chapter 13 Solutions

Developmental Mathematics (9th Edition)

Ch. 13.1 - Prob. 1SR Ch. 13.1 - Prob. 2SR Ch. 13.1 - Prob. 1DE Ch. 13.1 - Prob. 2DE Ch. 13.1 - Prob. 3DE Ch. 13.1 - Prob. 4DE Ch. 13.1 - Prob. 5DE Ch. 13.1 - Prob. 6DE Ch. 13.1 - Prob. 7DE Ch. 13.1 - Prob. 8DE

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The actual dimensions of a cross section of a two-by-four piece of lumber if the the perimeter is 10 in and the length is 2 in more than the width.

Solution Summary: The author calculates the actual dimensions of a two-by-four piece of lumber if the perimeter is 10in and the length is

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To calculate: The actual dimensions of a cross section of a two-by-four piece of lumber if the the perimeter is 10 in and the length is 2 in more than the width.

Want to see the full answer?

Chapter 13 Solutions

To calculate: The actual dimensions of a cross section of a two-by-four piece of lumber if the

the perimeter is 10 in and the length is 2 in more than the width.