Explanation Given Information: The provided equation is 1 x + 1 − 1 x = 2 x − 2 . Formula used: The distributive property for any numbers a , b and c is a ( b + c ) = a b + a c . Zero factor property is such that, if m n = 0 then either m = 0 or n = 0 , or both m = 0 and n = 0 . Calculation: Consider the equation, 1 x + 1 − 1 x = 2 x − 2 Multiply both sides by x ( x + 1 ) ( x − 2 ) , x ( x + 1 ) ( x − 2 ) ( 1 x + 1 − 1 x ) = x ( x + 1 ) ( x − 2 ) ( 2 x − 2 ) x ( x − 2 ) − ( x + 1 ) ( x − 2 ) = 2 x ( x + 1 ) Use the distributive property, x 2 − 2 x − ( x 2 − 2 x + x − 2 ) = 2 x 2 + 2 x x 2 − 2 x − x 2 + 2 x − x + 2 = 2 x 2 + 2 x − x + 2 = 2 x 2 + 2 x 0 = 2 x 2 + 3 x − 2 Make the factors, 2 x 2 + 3 x − 2 = 0 2 x 2 + 4 x − x − 2 = 0 2 x ( x +

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ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Chapter 13.3, Problem 44ES

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To calculate: The solution of the equation 1x+1−1x=2x−2.

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Chapter 13.3, Problem 43ES

Chapter 13.3, Problem 45ES

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Chapter 13 Solutions

Developmental Mathematics (9th Edition)

Ch. 13.1 - Prob. 1SR Ch. 13.1 - Prob. 2SR Ch. 13.1 - Prob. 1DE Ch. 13.1 - Prob. 2DE Ch. 13.1 - Prob. 3DE Ch. 13.1 - Prob. 4DE Ch. 13.1 - Prob. 5DE Ch. 13.1 - Prob. 6DE Ch. 13.1 - Prob. 7DE Ch. 13.1 - Prob. 8DE

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The solution of the equation 1 x + 1 − 1 x = 2 x − 2 .

Solution Summary: The author explains the formula used to calculate the equation 1x+1-

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To calculate: The solution of the equation 1x+1−1x=2x−2.

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Chapter 13 Solutions