Explanation Refer to Table A-1, obtain the molar masses of O 2 , N 2 , and Ar are as follows: M O 2 = 32 .0 kg/kmol M N 2 = 28. 0 kg/kmol M Ar = 40. 0 kg/kmol Consider 100 kmol of air. N O 2 = 21 kmol N N 2 = 78 kmol N Ar = 1 kmol Calculate the mass of O 2 . m O 2 = N O 2 M O 2 (I) Calculate the mass of N 2 . m N 2 = N N 2 M N 2 (II) Calculate the mass of Ar . m Ar = N Ar M Ar (III) Calculate the total mass of the mixture. m m = m O 2 + m N 2 + m Ar (IV) Calculate the percentage of mass fraction of O 2 . mf O 2 = m O 2 m m × 100 % (V) Calculate the percentage of mass fraction of N 2 . mf N 2 = m N 2 m m (VI) Calculate the percentage mass fraction of Ar . mf Ar = m Ar m m (VII) Calculate the molar mass of the mixture. M m = m m N m (VIII) Here, mole number of the mixture is N m . Conclusion: Substitute 21 kmol for N O 2 and 32 kg/kmol for M O 2 in Equation (I). m O 2 = ( 21 kmol ) ( 32 kg/kmol ) = 672 kg Substitute 78 kmol for N N 2 and 28 kg/kmol for M N 2 in Equation (II)

9th Edition

ISBN: 9781260917055

Author: CENGEL

Publisher: MCG

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Properties of Pure Substances

A substance with fixed chemical composition throughout is called a pure substance like water, air, and nitrogen. A pure substance does not have to be a single element or compound. A mixture of two or more phases of a pure substance is also a pure substan…

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Chapter 13.3, Problem 85RP

To determine

The mass fraction of O2, N2, and Ar.

The molar mass of the mixture.

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Chapter 13.3, Problem 84P

Chapter 13.3, Problem 86RP

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Chapter 13 Solutions

CENGEL'S 9TH EDITION OF THERMODYNAMICS:

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