Chapter 13.3, Problem 3CP

Interpretation Introduction

Interpretation:

The molarity of the solution is to be calculated.

Concept Introduction:

Molarity is defined as the total number of moles of solute present in one litre of the solution.

Mathematically, it can be expressed as follows:

$\text{Molarity }\left(M\right)=\frac{\text{moles of solute}}{\text{litre of solution }}$

$\text{No}\text{. of moles}=\frac{\text{mass }}{\text{molar mass }}$

The relation between volume and density is expressed as follows:

$d=\frac{\text{m}}{\text{V}}$

Here, $d$ is the density of the solution, m is the mass of the solution and V is the volume of the solution.

Molality is defined as the total number of moles present in one kilogram of the solvent.

Mathematically, it can be expressed as follows:

$\text{molality }\left(m\right)=\frac{\text{moles of solute}}{\text{mass of solvent }\left(\text{in Kg}\right)}$