Given a finite-state automaton
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- Exercises 7. Express each permutation in Exercise as a product of transpositions. 1. Express each permutation as a product of disjoint cycles and find the orbits of each permutation. a. b. c. d. e. f. g. h.arrow_forwardFind the order of each permutation in Exercise 1. Express each permutation as a product of disjoint cycles and find the orbits of each permutation. a. [ 1234545312 ] b. [ 1234513254 ] c. [ 1234541352 ] d. [ 1234535241 ] e. [ 12345673456127 ] f. [ 12345675137264 ] g. [ 1234513452 ][ 1234532415 ] h. [ 1234523415 ][ 1234513542 ]arrow_forwardExercises 3. In each part of Exercise , decide whether the permutation is even or odd. 1. Express each permutation as a product of disjoint cycles and find the orbits of each permutation. a. b. c. d. e. f. g. h.arrow_forward
- Prove statement d of Theorem 3.9: If G is abelian, (xy)n=xnyn for all integers n.arrow_forwardLet T be a linear transformation from M2,2 into M2,2 such that T([1000])=[1102], T([0100])=[0211], T([0010])=[1201],T([0001])=[3110]. Find T([1314]).arrow_forward团 homeork.docx > Homework-1: Prove by induction: 1) 2+4 +6 + . . + 2n = n (n + 1) 2) 1 +4 +7+.. + (3n – 2) = 1/2 n ( 3n - 1) Home work -2: 1) Consider the following relations on the set A = {1, 2, 3}: R = {(1, 1), (1, 2), (1, 3), (3, 3)}, S= {(1, 1)(1, 2), (2, 1)2, 2). (3, 3)}, T= {(1, 1), (1, 2), (2, 2), (2, 3)} Ø = empty relation Ax A= universal relation Determine whether or not each of the above relations on A is: (a) reflexive; (b) symmetric; (c) transitive; (d) antisymmetric. (e) Compatibility. () Partial ordered relation. Homework -3: For the relation R = {(a, a), (a, b), (b, c), (c, c)} on the set A = {a, b, c}. Find: (a) reflexive(R); (b) symmetric(R); (c) transitive(R).arrow_forward
- Draw the Hasse diagram for the partial ordering {(A, B) / ACB} on the power set P (S) where S {a,b,c}. In any Boolean algebra, show that a = 0 e a b'+ a' b = b. Define Modular Lattice. Prove that every distributive lattice is modular.arrow_forwardLet B denote a Boolean algebra. Prove the identity V a, b e B, (a · b = 0) ^ (a + b = 1) = a = b. That is, prove the complement b is the unique element of B which satisfies (b · b = 0)^ (b + b = 1).arrow_forwardam1) E Math455-Ex(II) I SSCI1215 Assignment 2 e.com/forms/d/e/1FAlpQLSeHO3DzeAFIAnWKKu0TIUHItofjDmd5FE2qtdCMF9XdW_wxZA/formResponse = {ø, X, {m},{n}}. Q. Let X = {m, n}, and Define the function u,:- [0, 00) by %3D 3 if n E A 0 if n ¢ A a. Hn is a measure and u, ({m, n}\{n}) = 0 Ho (A) = then b. u, is not a measure. c. Hn is a measure and p, ({n}\{m}) = 3 d. None of these. a FUJITSUarrow_forward
- Let A be the set of all strings of 0's and 1's, and let T be the set of all strings of 0's and 1's that consist of consecutive triples of identical bits. Consider the coding and decoding functions E and D defined in Example 7.1.9. The encoding function E: A → T is defined as follows. For each string s ∈ A, E(s) = the string obtained from s by replacing each bit of s by the same bit written three times. The decoding function D: T → A is defined as follows. For each string t ∈ T, D(t) = the string obtained from t by replacing each consecutive triple of three identical bits of t by a single copy of that bit. (a) Find E (0110) and D (111111000111). (b) Find E (1010) and D (000000111111).arrow_forwardA single card is drawn randomly (with replacement) from 52-card deck. Let A denotes that the card is red; B denotes the card is a face card, and C denotes that it is King (K). a) Find P (A), P (B) , P (C) b) P (A|B), and P(C|B) means conditional c) Prove the dependency/independency of (A & B) and ( B & C) Note: There are 12 face cards, 4 kings, 26 red cards and 26 black cardsarrow_forward(ii) for every singleton set A, m* (A) = 0.arrow_forward
- Elements Of Modern AlgebraAlgebraISBN:9781285463230Author:Gilbert, Linda, JimmiePublisher:Cengage Learning,Linear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage LearningElementary Linear Algebra (MindTap Course List)AlgebraISBN:9781305658004Author:Ron LarsonPublisher:Cengage Learning