Explanation Given: m = 3 kg . k = 1200 N/m . l o = 0.5 m . Let position 1 be the initial position. r 1 = 0.3 m ( v r ) 1 = 0 ( v θ ) 1 = 2 m / s v 1 = 2 m / s x = r 1 − l o = 0.3 − 0.5 = − 0.2 m T 1 = 1 2 m v 2 = 1 2 ( 3 ) ( 2 ) 2 = 6 J V 1 = 1 2 k x 1 2 = 1 2 ( 1200 ) ( − 0.2 ) 2 = 24 J Let position 2 be when r is maximum. ( v r ) 2 = 0 r 2 = r m x 2 = ( r m − 0.5 ) T 2 = 1 2 m v 2 2 = 1 2 ( 3 ) ( v θ ) 2 2 = 1.5 ( v θ ) 2 2 V 2 = 1 2 k x 2 2 = 1 2 ( 1200 ) ( r m − 0 To determine (b) The corresponding speed.

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Forced undamped vibrations

In mechanical engineering, vibration is expressed as the term that occurs due to an object's backward and forward movement about a point of equilibrium. Generally, there are three types of vibrations which are,

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Chapter 13.2, Problem 13.94P

To determine

(a)

Maximum distance between origin and collar.

To determine

(b)

The corresponding speed.

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Chapter 13.2, Problem 13.93P

Chapter 13.2, Problem 13.95P

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(a) Maximum distance between origin and collar.

Solution Summary: The author explains the maximum distance between origin and collar.