(a) Explanation Given information: The force ( F ) is ( k x + y ) i + ( k x + y ) j . Calculation: Show the force acting on the member AB as in Figure (1). Write the expression for the work done on the member AB ( U A B ) as follows: U A B = ∫ 0 a k x d x = k [ x 2 2 ] 0 a = k [ a 2 2 − 0 ] = k a 2 2 The force F in the x and y are equal. Thus the force F is normal to the member BC so, the work done ( U B C ) is zero. Show the force acting on the member CA as in Figure (2). Write the expression for the work done on the member CA ( U C A ) as follows: U C A = ∫ 0 a − ( a − u ) d u (b) To determine The work of force F ( U A B C A ) .

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ISBN: 9781259633133

Author: BEER

Publisher: MCG

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Chapter 13.2, Problem 13.81P

(a)

To determine

The work of force F (UABCA).

(b)

To determine

The work of force F (UABCA).

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Chapter 13.2, Problem 13.80P

Chapter 13.2, Problem 13.82P

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