Let
(a) Express
(b) In words, what do the derivatives
(c) In words, what do the derivatives
Want to see the full answer?
Check out a sample textbook solutionChapter 13 Solutions
Calculus Early Transcendentals, Binder Ready Version
Additional Math Textbook Solutions
Calculus: Single And Multivariable
Precalculus: Mathematics for Calculus (Standalone Book)
Precalculus: Mathematics for Calculus - 6th Edition
University Calculus: Early Transcendentals (4th Edition)
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
University Calculus: Early Transcendentals (3rd Edition)
- TRUE OR FALSE. A plane curve C defined by the parametric equations x = f(t) and y = g(t), where t is in the closed interval [a,b], is said to be smooth if f'(t) and g'(t) are not both zero at every number in the open interval (a,b).arrow_forwardHuarrow_forwardClassify all level curves of f(x, y) = Vy² – x² and draw its contour map. -arrow_forward
- Write parametric equations for the tangent line to the curve of intersection of the surfaces x= y and y = 9z at the point (81,9,1). O A. x= 162t + 81, y= 9t +9, z=t+1 O B. x= 324t + 81, y = 9t+9, z=t+1 O C. x- 324t + 81, y = 18t +9, z =t+1 O D. x= 162t + 81, y = 18t +9, z=t+ 1 Click to select your answer. ch a 61arrow_forwardIf z = f (x, y) is a smooth continuous surface such that f.(a,b) =0 and f, (a,b) = 0 then what can you say about the tangent plane, normal line, and the behavior of the surface at the point (a,b, f(a,b))? Use complete sentences please.arrow_forwardLet f(x,y)= x2-y2 a) On the set of xy-axes, draw the level curves L(x,y) = k for k= 1,2,3. On another set of axes, draw the level curves f(x,y)= k for k=1,2,3. (Do this part by hand) b) How do the contour maps in part (a) reflect the fact that L is the linear approximation to f at the point (2,1)? Explain briefly in words.arrow_forward
- I'm stuck on this one. I need help please & thank you!!arrow_forwardConsider the surface S of equation || x² + y*" An equation for the tangent line tangent to S at point P(-3,1, o) in the direction of vector w = (-1,-1), corresponds to: -1 -3/2 1 +t. 10 1 A) (x, y, 2) = (- -3,1, teR 2 50 (금 -1 -1 -3 B) ( - (x, y, z) = -3,1, t ER +t. V2' V2' 25 (x, y, z) = ( –3, 1, ) 1 +t. -3/2 -1, -1, 50 teR D) (=,».9) = (-3,1) +* -1) -1, -1, 25/2, +t. teRarrow_forwardFind the equation of the tangent plane to the surface of the equation z = x2 + y2 - 2xy on the point P(2,1,4)arrow_forward
- Use the contour diagram for f(x, y) shown below to estimate the directional derivative of f in the direction v at the point P. (a) At the point P = (2, 2) in the direction v = j, the directional derivative is approximately (b) At the point P = (2,3) in the direction=-7, the directional derivative is approximately D (c) At the point P = (4, 1) in the direction. v = (i+j)/√2, the directional derivative is approximately (d) At the point P = (4,0) in the direction v = −ỉ, the directional derivative is approximatelyarrow_forwardFor an implicit surface determined by the implicit relation function F (x, y, z) =0, it is known that its tangent plane is given by 3x −y + 2z = 12 at the pointP (5, 5, 1). Find the directional derivative ∇uF (P ) where u = (2, 2, −1)arrow_forwardGiven f(x, y, z) = x²y + y²z+z²x. (a) Find Vf(x, y, z). (b) Find the equation of the tangent plane to the surface f(x, y, z) = -1 at the point. (2,−1, 1). (c) Find the directional derivative of f(x, y, z) at the point (2, -1, 1) in the direction of the point (5, 1, 7).arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning