Campbell Biology in Focus
3rd Edition
ISBN: 9780134710679
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Rebecca Orr
Publisher: PEARSON
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Chapter 13, Problem 6TYU
Summary Introduction
Introduction:
The restriction enzymes cut the sequences of the DNA, which are palindromic repeat sequences. The enzymes cut the DNA, according to the specificity of the sequence.
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Choose the combination of answers that most accurately completes the statement.Which of the following sequences, when combined with its complement, would be clipped by a restriction endonuclease? a. ATCGATCGTAGCTA c. GAATTC b. AAGCTTCGAA d. ACCATTGGA
If a restriction endonuclease recognizes and cleaves a linear piece of DNA and Circular DNA at 8 distinet places, how many pieces will result?
OA Nine and Eight fragments respectively
B.
Both gerierate nine fragments
C.
Ten and nine fragments respectively
Both generate eight fragments
Which of the following is a sequence most likely to be recognized by restriction enzymes?
a. 5' GATTAATC 3' - double-strand form
b. 5' ATG 3' - double-strand form
c. 5' AUGCGCAU 3' - double-strand form
d. NH3-met-trp-val- COOH
e. none of the above
Chapter 13 Solutions
Campbell Biology in Focus
Ch. 13.1 - Given a polynucleotide sequence such as GAATTC,...Ch. 13.1 - Prob. 2CCCh. 13.2 - What role does base pairing play in the...Ch. 13.2 - Make a table listing the functions of seven...Ch. 13.2 - MAKE CONNECTIONS What is the relationship between...Ch. 13.3 - Describe the structure of a nucleosome, the basic...Ch. 13.3 - What two properties, one structural and one...Ch. 13.4 - Prob. 1CCCh. 13.4 - DRAW IT One strand of a DNA molecule has the...Ch. 13.4 - Describe the role of complementary base pairing...
Ch. 13 - In his work with pneumonia-causing bacteria and...Ch. 13 - Prob. 2TYUCh. 13 - In analyzing the number of different bases in a...Ch. 13 - The elongation of the leading strand during DNA...Ch. 13 - Prob. 5TYUCh. 13 - Prob. 6TYUCh. 13 - Prob. 7TYUCh. 13 - Prob. 8TYUCh. 13 - Prob. 9TYUCh. 13 - MAKE CONNECTIONS Although the proteins that cause...Ch. 13 - Prob. 11TYUCh. 13 - FOCUS ON EVOLUTION Some bacteria may be able to...Ch. 13 - FOCUS ON ORGANIZATION The continuity of life is...Ch. 13 - Prob. 14TYU
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Which of the sequences below would serve as a PCR primer that would bind this DNA strand: 5'- AAATTTGGGCCCTTTGGGAAACCC-3, and lead to successful elongation? Select one: O a. 5'-GGGTTTCCC-3" O b.3'-GGGTTTCCC-5" O c. 5'-AAATTTGGG-3 O d.3'-AAATTTGGG-5 O e. 5'-CCCAAAGGG-3"arrow_forwardYou are presented with the following DNA molecule: 5’ A T G C G A T T A T A A 3’ 3’ T A C G C T A A T A T T 5’ A. Write the template DNA strand B. Transcribe the template DNA strand into mRNA C. Translate the mRNA into an amino acid sequencearrow_forwardIf you have got the following DNA template molecules, which one of them will require more energy to break down the hydrogen bonds between the antiparallel strands? O a. ATATATATCGCGTTAAATTCTA O b. GCGCGCGCGCGCGCGCGCGCG O c. AAAAAATTTTTCCCCCGGGGG O d. TACTACACTGTGGTTAATTAAA O e. GGGGGCCCCCAATTCCCCCCC tune of proteins that heln in regulating the levels of different molecules in human body, e.garrow_forward
- What is the enzymatic function of restriction enzymes? Group of answer choices a. to cut nucleic acids at specific sites b. to join nucleotides during transcription c. to add new nucleotides to the growing strand of DNA d. to repair breaks in sugar - phosphate backbonesarrow_forwardA new restriction enzyme is discovered. It recognizes a 6 base pair pallindromic sequence. The first three bases of the target sequence are are given below with the cut identified by ^. Answer the following questions: Target sequence: 5' G^TA _ _ _ 3'3' _ _ _ _ _ _ 5' 1) Complete the target sequence with all missing bases. Also include the position of the cut in the lower sequence(^) 2) What kind of clevage does the enzyme use?arrow_forwardWhat is used to cut the DNA in panels 1 and 2? a. Restriction enzymes b. DNA polymerases c. DNA ligases d. RNA polymerases e. Reverse transcriptasearrow_forward
- Use the set of gene sequencing results below to answer the question that follows: A G C T -Wells I 14. Based on the sequencing results above, what is the sequence of nucleotides as they were added by DNA polymerase to the DNA template? a/ATC-GCA-GTA b. TAG-TGC-CAT c. TAC-TGC-GAT GC-GA TAG-CGT-CAT L A EI la la اد ان YIarrow_forwardIf the following is a restriction enzyme: Sma I, A. What is the first letter represent? B. What do the next two letters represent? C. What does the roman numeral represent?arrow_forwardYou isolated a 10,500 base pair plasmid (supercoiled, cccDNA) from E. coli. The plasmid contains one unique recognition site for EcoRI, a restriction enzyme. Restriction enzymes recognize a specific sequence and cut both strands of the DNA at that sequence (Chapter 7). Brief DNase I treatment breaks one (or very few) phosphodiesterbonds in each DNA molecule, leaving the double-stranded DNA with one strand broken but the other strand intact, i.e “nicked.” You briefly incubated the cccDNA at 37°C in four separate reactions containing the components listed below. You ran each reaction sample on an agarose gel and visualized the DNA using ethidium bromide and UV light. The reactions included the appropriate buffer and ATP when required. An agarose gel containing four lanes of possible products is given below. Please refer to Figs. 4-26 and 4-27 in Watson for reference. For each reaction, indicate which lane of the gel contains the products that you would expect to see on your…arrow_forward
- A mutant DNA strand was transcribed then translated to proteins. a. What is the protein product of the mutant DNA strand? The sequence of the mutant strand is shown below: 5'-TGCCATAACTGTTCGTACTGGCAAATTGCC-3' 3'-ACGGTATTGACAAGCATGACCGTTTAACGG-5' b. The mutation altered the sequence of the wild type template DNA such that a degenerate codon for a basic amino acid in the wild type was converted to a non-degenerate codon resulting in the sequence for the mutant strand shown. What was the original amino acid? c. Compare the charges and pl of the mutant peptide and the normal (wild- type) peptide at physiological pH?arrow_forwardThe enzyme responsible for the joining of Okazaki fragments is a. helicase b. primase c. DNA ligase d. DNA topoisomerasearrow_forwardA restriction endonuclease, REI, recognize AAGCTT and cleaves between A and A in the sequence. Given a DNA segment in Figure 2, draw to show the sticky end products after this DNA segment is reacted with REI. 5 Č ČÁ Á G G GT T CGAAC 3'L 5' Figure 2arrow_forward
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