Bundle: Biology: The Unity and Diversity of Life, Loose-leaf Version, 14th + LMS Integrated for MindTap Biology, 2 terms (12 months) Printed Access Card
14th Edition
ISBN: 9781305775480
Author: Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Publisher: Cengage Learning
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Chapter 13, Problem 5SQ
Summary Introduction
Concept introduction: The parent genotypes if known will help to determine the possible genotypes of children based on the Mendelian monohybrid cross and dihybrid cross. The parents can be homozygous dominant or homozygous recessive or heterozygous individuals.
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Match the terms with the best description.___ dihybrid cross a. bb___ monohybrid cross b. AaBb × AaBb___ homozygous condition c. Aa___ heterozygous condition d. Aa × Aa
Assuming complete dominance, a cross between dihybrid F1 pea plants produces F2 phenotype ratios of____ . a. 1:2:1 b. 3:1 c. 1:1:1:1 d. 9:3:3:1
A test cross is performed to determine if a specific individual is a carrier. The results generate a 50/50 ratio of phenotypes. The test subject is therefore ________.
A. Unable to reproduce
B. Homozygous recessive
C. Not following the rules of Mendelian genetics
D. Homozygous dominant
E. Heterozygous
Chapter 13 Solutions
Bundle: Biology: The Unity and Diversity of Life, Loose-leaf Version, 14th + LMS Integrated for MindTap Biology, 2 terms (12 months) Printed Access Card
Ch. 13 - A heterozygous individual has a _______ for a...Ch. 13 - An organisms observable traits constitute its...Ch. 13 - Prob. 3SQCh. 13 - The second-generation offspring of a cross between...Ch. 13 - Prob. 5SQCh. 13 - Refer to question 5. Assuming complete dominance,...Ch. 13 - Prob. 7SQCh. 13 - Prob. 8SQCh. 13 - The probability of a crossover occurring between...Ch. 13 - True or false? All traits are inherited in a...
Ch. 13 - Prob. 11SQCh. 13 - The phenotype of individuals heterozygous for...Ch. 13 - Prob. 13SQCh. 13 - Match the terms with the best description. ______...Ch. 13 - Assuming that independent assortment occurs during...Ch. 13 - Refer to problem 2. Determine the predicted...Ch. 13 - Refer to problem 2. Assume a third gene has...Ch. 13 - Prob. 4GPCh. 13 - Suppose you identify a new gene in mice. One of...Ch. 13 - Mendel crossed a true-breeding pea plant with...Ch. 13 - Several alleles affect traits of roses, such as...Ch. 13 - Prob. 1DAACh. 13 - Prob. 2DAACh. 13 - Prob. 3DAACh. 13 - Mutations in the TYR gene may render its enzyme...Ch. 13 - In sweet pea plants, an allele for purple flowers....Ch. 13 - Red-flowering snapdragons are homozygous for...Ch. 13 - A single allele gives rise to the Hbs form of...
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- Color blindness is inherited in a(n)_____ pattern. a. autosomal dominant c. X-linked dominant b. autosomal recessive d. X-linked recessivearrow_forwardA mother who is blood type a B has a child who is a B also. A potential father‘s blood type O. A geneticist concludes that. A. He cannot be the father B. He is very likely to be the father C. No conclusion can be drawnarrow_forwardKlinefelter syndrome (XXY) can most be easily diagnosed by_______ . a. pedigree analysis c. karyotyping b. aneuploidy d. phenotypic treatmentarrow_forward
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- A BOOKMARK E- Question 4/28 NEXT Which Punnett square shows a cross between a heterozygous tall (Tt) plant and a homozygous short (tt) pea plant? C. A. Tt tt TT TT Tt tt TT TT D. В. Tt Tt tt tt Tt Tt tt tt C DDarrow_forwardEye color is a Mendelian trait. A. True B. Falsearrow_forwardThe probability of a crossover occurring between two genes on the same chromosome_____ . a. is unrelated to the distance between them b. decreases with increasing distance between them c. increases with the distance between themarrow_forward
- Joe has classic hemophilia, an X-linked recessive disease. Could Joe have inherited the gene for this disease from the following people? Yes No a. His mother's mother b. His mother's father c. His father's mother d. His father's fatherarrow_forwardCircles are females and squares are males. "a" indicated albinism. Refer to to the figure to show the probabilty that each pair would have an albino child. a. 7x14 b. 2x12arrow_forwardAn individual with two different alleles at a locus is a(n) Group of answer choices A. clone B. hemizygote C. homozygote D.heterozygotearrow_forward
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