The solvent and the solute between the given species is to be identified. The reaction to separate the tin from the bronze is to be stated. The concentration of tin in bronze is to be calculated. Concept introduction: A solution is a homogeneous mixture of two or more substances and the composition is same throughout the solution. The solute and the solvent are the components of the solution. Alloy is a mixture of metal with another metal or metal with another element. To determine: The components of the solution.
The solvent and the solute between the given species is to be identified. The reaction to separate the tin from the bronze is to be stated. The concentration of tin in bronze is to be calculated. Concept introduction: A solution is a homogeneous mixture of two or more substances and the composition is same throughout the solution. The solute and the solvent are the components of the solution. Alloy is a mixture of metal with another metal or metal with another element. To determine: The components of the solution.
Interpretation: The solvent and the solute between the given species is to be identified. The reaction to separate the tin from the bronze is to be stated. The concentration of tin in bronze is to be calculated.
Concept introduction: A solution is a homogeneous mixture of two or more substances and the composition is same throughout the solution.
The solute and the solvent are the components of the solution.
Alloy is a mixture of metal with another metal or metal with another element.
To determine: The components of the solution.
(b)
Interpretation Introduction
To determine: The concentration of the solute metal present in the given alloy.
(c)
Interpretation Introduction
To determine: The reaction to remove all the tin from the bronze.
Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following:
(a) match structures of isomers given their mass spectra below (spectra A and spectra B)
(b) Draw the fragments given the following prominent peaks from
each spectrum:
Spectra A m/2 =43 and 1/2-57
spectra B m/2 = 43
(c) why is 1/2=57 peak in spectrum A more intense compared
to the same peak in spectrum B.
Relative abundance
Relative abundance
100
A
50
29
29
0
10
-0
-0
100
B
50
720
30
41
43
57
71
4-0
40
50
60 70
m/z
43
57
8-0
m/z = 86
M
90 100
71
m/z = 86
M
-O
0
10 20 30
40 50
60
70
80
-88
m/z
90
100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass
spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained.
Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.
Chapter 13 Solutions
Chemistry the Central Science 13th Edition Custom for Lamar University
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