
Concept explainers
(a)
Interpretation: The weight percentage of
Concept introduction:
Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture
Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by
The number of moles of any substance can be determined using the equation
Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.
(a)

Answer to Problem 56GQ
Weight percentage of
Explanation of Solution
Given,
Given mass of
Given mass of ice is
Weight percentage of
Weight percentage of
(b)
Interpretation: The mole fraction of
Concept introduction:
Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture
Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by
The number of moles of any substance can be determined using the equation
Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.
(b)

Answer to Problem 56GQ
Mole fraction of
Explanation of Solution
Given,
Given mass of
Given mass of ice is
Molar mass of
Molar mass of ice is
Number of moles of
Number of moles of ice is,
Mole fraction of
Mole fraction of
(c)
Interpretation: The molality of the solution of
Concept introduction:
Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture
Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by
The number of moles of any substance can be determined using the equation
Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.
(c)

Answer to Problem 56GQ
Molality of the solution is
Explanation of Solution
Given,
Given mass of
Given mass of ice is
Molar mass of
Molar mass of ice is
Number of moles of
Number of moles of ice is,
Molality of the solution is calculated,
Molality of the solution is
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Chapter 13 Solutions
CHEMISTRY+CHEM...HYBRID ED.(LL)>CUSTOM<
- Michael Reactions 19.52 Draw the products from the following Michael addition reactions. 1. H&C CH (a) i 2. H₂O* (b) OEt (c) EtO H₂NEt (d) ΕΙΟ + 1. NaOEt 2. H₂O' H H 1. NaOEt 2. H₂O*arrow_forwardRank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic. НОН НЬ OHd Онсarrow_forwardCan the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? ? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C :0 T Add/Remove step Garrow_forward
- The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJarrow_forwardA covalent bond is the result of the a) b) c) d) e) overlap of two half-filled s orbitals overlap of a half-filled s orbital and a half-filled p orbital overlap of two half-filled p orbitals along their axes parallel overlap of two half-filled parallel p orbitals all of the abovearrow_forwardCan the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C T Add/Remove step X ноarrow_forward
- Which one of the following atoms should have the largest electron affinity? a) b) c) d) 으으 e) 1s² 2s² 2p6 3s¹ 1s² 2s² 2p5 1s² 2s² 2p 3s² 3p² 1s² 2s 2p 3s² 3p6 4s2 3ds 1s² 2s² 2p6arrow_forwardAll of the following are allowed energy levels except _. a) 3f b) 1s c) 3d d) 5p e) 6sarrow_forwardA student wants to make the following product in good yield from a single transformation step, starting from benzene. Add any organic reagents the student is missing on the left-hand side of the arrow, and any addition reagents that are necessary above or below the arrow. If this product can't be made in good yield with a single transformation step, check the box below the drawing area. Note for advanced students: you may assume that an excess of benzene is used as part of the reaction conditions. : ☐ + I X This product can't be made in a single transformation step.arrow_forward
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