BIOCHEMISTRY (LOOSELEAF)-W/ACCESS
9th Edition
ISBN: 9781319425784
Author: BERG
Publisher: Macmillan Higher Education
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Question
Chapter 13, Problem 31P
Interpretation Introduction
Interpretation:
The differentiation of the transport mechanisms of indole and glucose needs to be explained. If ouabain inhibits the mechanism of transport of glucose, the information suggest by this inhibition about the mechanism of transport needs to be explained.
Concept introduction:
The transport of glucose and indole is represented in the following graph:
The exhibited curve is the transport curve which indicates that it needs a carrier for transportation.
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12:33
CO
Problem 7 of 15
4G. 53%
Submit
Using the following reaction data
points, construct a Lineweaver-Burk
plot by dragging the points to their
relevant coordinates on the graph
and drawing a line of best fit. Based
on the plot, determine the value of
Vmax. Report your answer to three
significant figures.
1
,
mM-1
1
[S]
V'
sμM-¹
100.0
0.100
75.0
0.080
50.0
0.060
15.0
0.030
10.0
0.025
5.0
0.020
Answer:
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Г
12:33
CO
Problem 5 of 15
4G 54%
Done
On the following Lineweaver-Burk
1
plot, identify the by dragging the
Vmax
point to the appropriate value on the
line.
NI
35
30-
25
20-
15-
10
5.
1
Vmax
-15
10
-5
0
5
10
15
20
20
|||
で
Г
25
30
1/[S]
12:20
V
0.1-
0:09.
0.08
0:07
0.06
-0.05-
0:04-
-0.03-
-0.02-
4G 56%
Problem 1 of 15
Done
On the following Michaelis-Menten
plot, estimate the value of - Vmax by
1
2
dragging the line to the appropriate
value on the y-axis.
0.01
V
max
0
0.5
|||
1.5
2.5
3.5
4
ISL
Chapter 13 Solutions
BIOCHEMISTRY (LOOSELEAF)-W/ACCESS
Ch. 13 - Prob. 1PCh. 13 - Prob. 2PCh. 13 - Prob. 3PCh. 13 - Prob. 4PCh. 13 - Prob. 5PCh. 13 - Prob. 6PCh. 13 - Prob. 7PCh. 13 - Prob. 8PCh. 13 - Prob. 9PCh. 13 - Prob. 10P
Ch. 13 - Prob. 11PCh. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Prob. 14PCh. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - Prob. 17PCh. 13 - Prob. 18PCh. 13 - Prob. 19PCh. 13 - Prob. 20PCh. 13 - Prob. 21PCh. 13 - Prob. 22PCh. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - Prob. 31PCh. 13 - Prob. 32P
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- 12:33 CO 4G 54% Problem 6 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the Km. 1 mM-1 1 [S]' " s mM-1 V 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forwardV 0.1- 0:09 0:08 0:07- -0.06 -0.05 0:04- 0:03 0:02 0:01- Problem 2 of 15 Done On the following Michaelis-Menten plot, estimate the value of Kм by dragging the point to the appropriate value on the x-axis. I T | 0 0.5 1.5 2 KM -0:01- ||| 25 2.5 3 3.5 4 Г [S] powered by desmosarrow_forward9. Sketch NMR of the following compound. Clearly label each H-atom in the molecule and where it appears in your NMR. Clearly label the splitting (coupling) pattern (singlet, doublet etc) for each set of equivalent protons. For each signal, clearly label the integration value or the number of protons represented by the signal. Brarrow_forward
- Please help with this Mass Spectrometry Question. Thank you For the mass spec. shown in the attached image, please determine and give the amino acid sequence of the pentapeptide. Show which end is the amino terminus and which is the carboxy terminus. How does one arrive at the solution?arrow_forwardDraw a tripeptide of your choosing at pH 7. Have the N-terminus on the left and the C-terminus on the right. Then: Draw a triangle around the α-carbons. Draw a box around the R-groups. Circle the atoms capable of hydrogen bonding. Highlight the atoms involved in the formation of the peptide bonds. What type of structure have you drawn? (primary, secondary, tertiary or quaternary protein structure).arrow_forward2. For the flow of fluid over a flat membrane of length 10cm, determine the length-average mass transfer coefficient. The relevant properties of the system are u=0.01cm²/s, D=5 x 106 cm²/s, and v = 5.0 cm/s.arrow_forward
- Background Freezing isn't the only challenge in cryopreservation - thawing can be just as difficult. A microwave oven seems like a nice solution, since it deposits energy quickly and microwaves are non-ionizing radiation (they do not cause DNA mutation). However, water absorbs microwaves more effectively than ice does, meaning that the portion of an organ that has already melted will get warmer at a higher rate than the remaining ice – the opposite of what we want! - The transmission of radiation through a weakly absorbing material such as ice or water can be modeled by Beer's law, which assumes that the rate of absorption at a depth x is proportional to the local radiation intensity I(x) times an absorption coefficient, which is often written as μ or a or just µ). Noting that absorption decreases the intensity, we can write a differential equation a Solving the differential equation with the boundary condition on the surface being gives the relationship For a standard microwave oven…arrow_forward3. Dry air is inhaled at a rate of 10 liter/min through a trachea with a diameter of 20 mm and a length of 125 mm. The inner surface of the trachea is at a normal body temperature of 37°C and may be assumed to be saturated with water. a. Assuming steady, fully developed flow in the trachea, estimate the mass transfer convection coefficient. b. Estimate the daily water loss (liter/day) associated with evaporation in the trachea.arrow_forward1. Conceptual questions a. What dimensionless group describes the relative importance of convection versus diffusion. Explain the physical basis of this group. b. For mass transfer from a flowing fluid to a reactive surface, explain how convection increases the flux of solute to the surface.arrow_forward
- Assessment +1501 pts /1600 Resources Solution ? Hint Sub bo Each pictured Lewis structure is invalid. Identify the error in each case. O Macmillan Learning :0▬▬0: Answer Bank wrong electron total :0- :F======F: octet-rule violation N :0:arrow_forward[s] mM V (M/s) Uninhibited 0.333 1.65 x 107 1.05 x 107 V (M/s) x 10' Inhibitor A V (M/s) x 107 Inhibitor B 0.794 x 107 0.40 1.86 x 107 1.21 x 107 0.893 x 107 0.50 2.13 x 107 1.43 x 107 1.02 x 107 0.666 2.49 x 107 1.74 x 107 1.19 x 107 1.0 2.99 x 107 2.22 x 107 1.43 x 107 2.0 3.72 x 107 3.08 x 107 1.79 x 107arrow_forwardFor a Michaelis-Menten reaction, k₁-5 x 10'/M-s, k.-2 x 10%/s, and k₂-4 x 10²/s. a) Calculate the Ks and KM for this reaction. b) Does substrate binding achieve equilibrium or steady state?arrow_forward
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