Introduction To General, Organic, And Biochemistry
12th Edition
ISBN: 9781337571357
Author: Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher: Cengage Learning
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Chapter 13, Problem 18P
Interpretation Introduction
Interpretation:Reason for glycerol being thicker than ethylene glycol and ethylene glycol being thicker than ethanol is to be determined.
Concept introduction: Viscosity is defined as quantification of the internal frictional force arising between adjacent layers of fluids in relative motion. In simpler words, it is defined as the resistance of a liquid to flow.
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 13 Solutions
Introduction To General, Organic, And Biochemistry
Ch. 13.1 - Prob. 13.1QCCh. 13.1 - Prob. 13.2QCCh. 13.2 - Problem 14-3 Draw structural formulas for the...Ch. 13.2 - Prob. 13.4QCCh. 13.2 - Prob. 13.5QCCh. 13.3 - Problem 14-6 Write the common name for each ether.Ch. 13.4 - Prob. 13.7QCCh. 13.4 - Prob. 13.8QCCh. 13 - 14-8 Answer true or false. The functional group of...Ch. 13 - 14-9 What is the difference in structure between a...
Ch. 13 - 14-10 Which of the following are secondary...Ch. 13 - 14-11 Which of the alcohols in Problem 14-10 are...Ch. 13 - 14-12 Write the 1UPAC name of each compound. (e)...Ch. 13 - Prob. 6PCh. 13 - Prob. 7PCh. 13 - 14-15 Both alcohols and phenols contain an —OH...Ch. 13 - Prob. 9PCh. 13 - 14-17 Explain in terms of noncovalent interactions...Ch. 13 - Prob. 11PCh. 13 - Prob. 12PCh. 13 - 14-20 Show hydrogen bonding between methanol and...Ch. 13 - 14-21 Show hydrogen bonding between the oxygen of...Ch. 13 - 14-22 Arrange these compounds in order of...Ch. 13 - 14-23 Arrange these compounds in order of...Ch. 13 - 14-24 2-Propanol (isopropyl alcohol) is commonly...Ch. 13 - Prob. 18PCh. 13 - Prob. 19PCh. 13 - Prob. 20PCh. 13 - 14-28 Give the structural formula of an alkene or...Ch. 13 - Prob. 22PCh. 13 - 14-30 Show how to distinguish between cyclohexanol...Ch. 13 - 14-31 Compare the acidity of alcohols and phenols,...Ch. 13 - 14-32 Both 2,6-diisopropylcyclohexanol and the...Ch. 13 - 14-33 Write equations for the reaction of...Ch. 13 - 14-34 Write equations for the reaction of...Ch. 13 - 14-35 Write equations for the reaction of each of...Ch. 13 - 14-36 Show how to convert cyclohexanol to these...Ch. 13 - Prob. 30PCh. 13 - Prob. 31PCh. 13 - 14-39 Name two important alcohols derived from...Ch. 13 - 14-40 Name two important alcohols derived from...Ch. 13 - Prob. 34PCh. 13 - 14-42 Write the common name for each ether. ch3...Ch. 13 - Prob. 36PCh. 13 - 14-44 Answer true or false. (a) The functional...Ch. 13 - Prob. 38PCh. 13 - Write the common name for each thiol in Problem 38...Ch. 13 - 14-47 Following are structural formulas for...Ch. 13 - 14-48 Explain why methanethiol, CH3SH, has a lower...Ch. 13 - 14-49 Answer true or false. Today, the major...Ch. 13 - (Chemical Connections 13A ) As stated in the...Ch. 13 - Prob. 44PCh. 13 - Prob. 45PCh. 13 - Prob. 46PCh. 13 - Prob. 47PCh. 13 - (Chemical Connections 13D ) Show that enflurane...Ch. 13 - Prob. 49PCh. 13 - 14-60 Write a balanced equation for the complete...Ch. 13 - 14-61 Knowing what you do about electronegativity,...Ch. 13 - 14-62 Draw structural formulas and write IUPAC...Ch. 13 - Prob. 53PCh. 13 - 14-64 Explain why the boiling point of ethylene...Ch. 13 - Prob. 55PCh. 13 - 14-66 1,4-Butanediol, hexane, and 1-pentanol have...Ch. 13 - 14-67 Of the three compounds given in Problem...Ch. 13 - Prob. 58PCh. 13 - 14-69 Show how to prepare each compound from...Ch. 13 - 14-70 Show how to prepare each compound from...Ch. 13 - 14-71 The mechanism of the acid-catalyzed...Ch. 13 - Prob. 62PCh. 13 - 14-73 Lipoic acid is a growth factor for many...Ch. 13 - 14-74 Following is a structural formula for the...Ch. 13 - Prob. 65PCh. 13 - Prob. 66PCh. 13 - Prob. 67PCh. 13 - 14-78 Consider alkenes A, B, and C. each of which...Ch. 13 - Prob. 69P
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- Please correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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