Explanation Given: Initial volume of water, V i = 55.5 m L Initial volume of the container, V i = 55.5 m L Initial temperature, T i = 20 ° C Final temperature, T f = 60 ° C Mass of water lost from the container on being heated, m w = 0.35 g Density of water at 60°C, ρ w = 0.98324 g m L Formula used: Δ V = β V i Δ T , where V i is the initial volume and β is the coefficient of volume expansion V = m ρ Calculation: The relation between change in volume of a substance (ΔV)and change in temperature (ΔT)is given by, Δ V = β V i Δ T --- (i), Where, V i is the initial volume and β is the coefficient of volume expansion In this case, the volume of water lost, Δ V = Δ V w – Δ V c --- (ii), Where, ΔV w is the change in volume of water and ΔV c is the change in volume of the container Since volume = m ρ , where m is mass and ρ is density The volume of water lost, Δ V = m w ρ w --- (iii) From equation (i), Δ V w = β w V i ( T f – T i ) To determine (b) To determine: The most likely material of the container

7th Edition

ISBN: 9780321625922

Author: Douglas C. Giancoli

Publisher: Addison-Wesley

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Ideal Gas Law

Ideal gas law states that the product of pressure and volume of a gas directly varies with the product of the number of moles, the universal gas constant, and the temperature of the gas.

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Question

Chapter 13, Problem 16P

To determine

(a) To determine:

The coefficient of volume expansion of the container

To determine

(b) To determine:

The most likely material of the container

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Chapter 13, Problem 15P

Chapter 13, Problem 17P

Chapter 13 Solutions

Physics: Principles with Applications

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