Chapter 13, Problem 160AE

(a)

Interpretation Introduction

Interpretation:

The equilibrium constant is to be calculated for ${\text{NH}}_3+{\text{H}}_{\text{3}}{\text{O}}^{+}\stackrel{}{\rightleftharpoons }{\text{NH}}_4{}^{+}+{\text{H}}_{\text{2}}\text{O}$.

Concept introduction:

The $K_{\text{b}}$ equilibrium constant is the ratio of product of equilibrium concentrations of product to the equilibrium concentration of reactant base.

(b)

Interpretation Introduction

Interpretation:

The equilibrium constant is to be calculated for ${\text{NO}}_2{}^{-}+{\text{H}}_{\text{3}}{\text{O}}^{+}\stackrel{}{\rightleftharpoons }{\text{HNO}}_2+{\text{H}}_{\text{2}}\text{O}$.

Concept introduction:

The $K_{\text{b}}$ equilibrium constant is the ratio of product of equilibrium concentrations of product to the equilibrium concentration of reactant base.

(c)

Interpretation Introduction

Interpretation:

The equilibrium constant is to be calculated for ${\text{NH}}_4{}^{+}+{\text{OH}}^{-}\stackrel{}{\rightleftharpoons }{\text{NH}}_3+{\text{H}}_{\text{2}}\text{O}$.

Concept introduction:

The $K_{\text{b}}$ equilibrium constant is the ratio of product of equilibrium concentrations of product to the equilibrium concentration of reactant base.

(d)

Interpretation Introduction

Interpretation:

The equilibrium constant is to be calculated for ${\text{HNO}}_2+{\text{OH}}^{-}\stackrel{}{\rightleftharpoons }{\text{H}}_{\text{2}}\text{O}+{\text{NO}}_2{}^{-}$.

Concept introduction:

The $K_{\text{b}}$ equilibrium constant is the ratio of product of equilibrium concentrations of product to the equilibrium concentration of reactant base.