Explanation Explanation To determine: The pH of solution containing 1.0 × 10 − 2 of HCl , 1.0 × 10 − 2 of H 2 SO 4 , and 1.0 × 10 − 2 HCN . The [ H + ] of HCl is 1 . 0 × 1 0 - 2 M _ . Given The concentration of HCl is 1.0 × 10 − 2 M . HCl is a monoprotic acid and dissociates as, HCl → H + + Cl − It is a strong acid and hence, dissociates completely in the solution; therefore, the total concentration of hydrogen ion is 1 . 0 × 1 0 - 2 M _ . The [ H + ] of H 2 SO 4 is 0 . 0 1 4 5 2 4 M _ . Given The concentration of H 2 SO 4 is 1.0 × 10 − 2 M . The acid H 2 SO 4 dissociates as, H 2 SO 4 → H + + HSO 4 − 1 The [ H + ] for this acid is 1.0 × 10 − 2 But H 2 SO 4 is a diprotic acid and dissociates in second step as, HSO 4 − 1 → H + + SO 4 2 − Initial (M) : 1.0 × 10 − 2 1.0 × 10 − 2 0 Change (M) : − x x x Equilibrium (M): 1.0 × 10 − 2 − x 1.0 × 10 − 2 + x x The equilibrium constant expression for the stated reaction is, K a 2 = [ H + ] [ SO 4 2 − ] [ HSO 4 − ] (1) Substitute values of concentration in the above equation. 1.2 × 10 − 2 = [ 1.0 × 10 − 2 ] [ x ] [ 1.0 × 10 − 2 − x ] x 2 − 2.2 × 10 − 2 x − 1.0 × 10 − 4 = 0 x = 0.004524 Hence, the total [ H + ] furnished by H 2 SO 4 = ( 1

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Chapter 13, Problem 150AE

Interpretation Introduction

Interpretation: The pH of the given aqueous solution is to be calculated.

Concept introduction: Strong acids have large values of Ka and dissociate completely in aqueous solutions.

The value of pH is calculated by the formula,

pH=−log[H+]

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Chapter 13, Problem 149AE

Chapter 13, Problem 151AE

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The pH of the given aqueous solution is to be calculated. Concept introduction: Strong acids have large values of K a and dissociate completely in aqueous solutions. The value of pH is calculated by the formula, pH = − log [ H + ]

Solution Summary: The author explains how the value of pH of the given aqueous solution is calculated.

Concept explainers

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Interpretation: The pH of the given aqueous solution is to be calculated.

Concept introduction: Strong acids have large values of Ka and dissociate completely in aqueous solutions.

The value of pH is calculated by the formula,

pH=−log[H+]

Want to see the full answer?

Chapter 13 Solutions

The pH of the given aqueous solution is to be calculated. Concept introduction: Strong acids have large values of K a and dissociate completely in aqueous solutions. The value of pH is calculated by the formula, pH = − log [ H + ]

Solution Summary: The author explains how the value of pH of the given aqueous solution is calculated.

Concept explainers

Videos

Interpretation: The pH of the given aqueous solution is to be calculated. Concept introduction: Strong acids have large values of Ka and dissociate completely in aqueous solutions. The value of pH is calculated by the formula, pH=−log[H+]

Want to see the full answer?

Chapter 13 Solutions

Interpretation: The pH of the given aqueous solution is to be calculated.

Concept introduction: Strong acids have large values of Ka and dissociate completely in aqueous solutions.

The value of pH is calculated by the formula,

pH=−log[H+]