Chapter 13, Problem 13.72P

Interpretation Introduction

Interpretation:

The mass of $\text{CsBr}$ that must be added to $0.500\text{L}$ of water to produce $0.400m$ is to be determined. Also, the mole fraction and mass percent of $\text{CsBr}$ is to be determined.

Concept introduction:

The mole fraction is defined as the ratio of the number of moles of solute to the total number of moles in the mixture. It is represented by $\text{X}$.

The formula to calculate the mole fraction is as follows:

$\text{Mole}\text{fraction}\left(\text{X}\right)=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}+\text{amount}\left(\text{mol}\right)\text{of}\text{solvent}}$ (1)

Mass percent is defined as the mass of a component divided by the total mass of the mixture, multiplied by 100.

The formula to calculate the mass percent is as follows:

$\text{Mass}\text{percent}=\frac{\text{mass}\text{of}\text{solute}}{\text{mass}\text{of}\text{solution}}\times 100$ (2)