Concept explainers
13-25 Answer true or false.
(a) Phenols and alcohols have in common the presence of an —OH group.
Phenols are weak acids and react with strong bases to give water-soluble salts.
- The pK„ of phenol is smaller than that of acetic acid.
(f, A characteristic of a chain initiation step is conversion of a nonradical to a radical.
(a)
Interpretation:
To analyse whether the given statement: Phenols and alcohols have in common the presence of an −OH group,is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
Phenols and alcohols have in common the presence of an −OH group. Thus, the statement is true.
Explanation of Solution
The alcohols are represented by a general formula: R-OH. In alcohols, the r is an alkyl group. The phenols are represented by a general formula: R-OH In phenol, the r is an aromatic benzene ring. An example of alcohol is methanol compared to phenol, as shown in the figure below:
Therefore, the given statement is true.
(b)
Interpretation:
To analyse whether the given statement: Phenols are weak acids and react with strong bases to give water-soluble salts, is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
Phenols are weak acids and react with strong bases to give water-soluble salts. Thus, the statement is true.
Explanation of Solution
Phenol is a weak acid. When it reacts with a strong base like sodium hydroxide NaOH, it forms water-soluble salt, or sodium phenoxide. Therefore, the given statement is true.
(c)
Interpretation:
To analyse whether the given statement: The
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
The
Explanation of Solution
The strength of an acid is measured by the acid dissociation constant Ka.
Consider this reaction.
The acid dissociation constant is given by the formula.
The pKa is the logarithmic measurement of the acid dissociation constant. We know that the pKa value for phenol is 10 and for acetic acid is 4.7. Hence, the pKa value of phenol is much greater than the pKa value of acetic acid. Therefore, the given statement is false.
(d)
Interpretation:
To analyse whether the given statement: Autoxidation converts an R-H group to an R-OH group, is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
Autoxidation converts an R-H group to an R-OOH group.Thus, the statement is false.
Explanation of Solution
Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. In auto-oxidation, the r — H group changes to an ROOH group and not to an ROH group. Therefore, the given statement is false.
(e)
Interpretation:
To analyze whether the given statement: A carbon radical has only seven electrons in the valence shell of one of its carbons, and this carbon bears a positive charge, is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
A carbon radical has only seven electrons in the valence shell of one of its carbons, and this carbon may bear a positive charge or negative charge of no charge.Thus, the statement is false.
Explanation of Solution
Radicals are atoms, molecules, or ions with unpaired electrons or untilled electrons in their valence shells. A radical may have a positive charge, a negative charge, or no charge. A carbon radical does not carry any charge on it. Therefore, the given statement is false.
(f)
Interpretation:
To analyze whether the given statement -A characteristic of a chain initiation step is conversion of a nonradical to a radical, is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
A characteristic of a chain initiation step is conversion of a nonradical to a radical. Thus, the statement is true.
Explanation of Solution
The characteristic of any chain initiation is the conversion of any non-radical to a radical. In a chain initiation process, hydrogen is converted to a hydrogen radical and carbon is converted to a carbon radical. For Example,
Therefore, the given statement is true.
(g)
Interpretation:
To analyze whether the given statement -Autoxidation is a radical-chain reaction, is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
Autoxidation is a radical-chain reaction. Thus, the statement is true.
Explanation of Solution
Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a diradical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound. Therefore, the given statement is true.
(h)
Interpretation:
To analyze whether the given statement -A characteristic of the chain propagation step is reaction of a radical and a molecule to form a new radical and a new molecule, is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Phenols act as antioxidants. Autoxidation is an oxidation reaction that requires only oxygen and no other reactants. It takes place in molecules containing carbon-carbon double bonds. Auto oxidation is a radical chain process. It takes place in different steps. In the first step, a non-radical compound changes to a radical form. For example, an oxygen atom is a di-radical. A radical reacts with oxygen to form a new radical. This new radical reacts with another molecule to form a new auto-oxidation product and a carbon radical compound.
Answer to Problem 13.25P
A characteristic of the chain propagation step is reaction of a radical and a molecule to form a new radical and a new molecule. Thus, the statement is true.
Explanation of Solution
A chain propagation step takes place in different steps. Autoxidation is an example of a chain propagation reaction. In the first step, a nonradical compound is changed to a radical form. Oxygen is a di-radical. A radical reacts with oxygen to form a new radical, which reacts with another radical and forms a carbon radical and a chain radical. Therefore, the given statement is true.
(i)
Interpretation:
To analyze whether the given statement -Vitamin E and other natural antioxidants function by interrupting the cycle of chain propagation steps that occurs in autoxidation, is true or not.
Concept Introduction:
Phenols are the compounds which have a hydroxyl group (—OH) bonded directly to a benzene ring. Phenol is a weak acid and pKa value for phenol is 10. Phenols are oxidized to quinone which is in turn easily reduced to hydroquinone.
Autoxidation is an oxidation reaction that requires only oxygen and no other reactants whereas the substance which inhibits oxidation is known as antioxidant.
Answer to Problem 13.25P
Vitamin E and other natural antioxidants function by interrupting the cycle of chain propagation steps that occurs in autoxidation. Thus the statement is true.
Explanation of Solution
Vitamin E is a stable radical. It breaks the chain propagation steps in auto-oxidation and prevents the formation of destructive hydro peroxides. Therefore, the given statement is true.
Want to see more full solutions like this?
Chapter 13 Solutions
Bundle: Introduction to General, Organic and Biochemistry, 11th + OWLv2, 4 terms (24 months) Printed Access Card
- Please correct answer and don't used hand raitingarrow_forward(11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)!arrow_forward. 3°C with TH 12. (10pts total) Provide the major product for each reaction depicted below. If no reaction occurs write NR. Assume heat dissipation is carefully controlled in the fluorine reaction. 3H 24 total (30) 24 21 2h • 6H total ● 8H total 34 래 Br2 hv major product will be most Substituted 12 hv Br NR I too weak of a participate in P-1 F₂ hv Statistically most favored product will be major = most subst = thermo favored hydrogen atom abstractor to LL Farrow_forward
- Five chemistry project topic that does not involve practicalarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardQ2. Consider the hydrogenation of ethylene C2H4 + H2 = C2H6 The heats of combustion and molar entropies for the three gases at 298 K are given by: C2H4 C2H6 H2 AH comb/kJ mol¹ -1395 -1550 -243 Sº / J K¹ mol-1 220.7 230.4 131.1 The average heat capacity change, ACP, for the reaction over the temperature range 298-1000 K is 10.9 J K¹ mol¹. Using these data, determine: (a) the standard enthalpy change at 800 K (b) the standard entropy change at 800 K (c) the equilibrium constant at 800 K.arrow_forward
- 13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)! Googlearrow_forwardPrint Last Name, First Name Initial Statifically more chances to abstract one of these 6H 11. (10pts total) Consider the radical chlorination of 1,3-diethylcyclohexane depicted below. 4 4th total • 6H total 래 • 4H total 21 total ZH 2H Statistical H < 3° C-H weakest - product abstraction here bund leads to thermo favored a) (6pts) How many unique mono-chlorinated products can be formed and what are the structures for the thermodynamically and statistically favored products? Product 6 Number of Unique Mono-Chlorinated Products Thermodynamically Favored Product Statistically Favored Product b) (4pts) Draw the arrow pushing mechanism for the FIRST propagation step (p-1) for the formation of the thermodynamically favored product. Only draw the p-1 step. You do not need to include lone pairs of electrons. No enthalpy calculation necessary H H-Cl Waterfoxarrow_forward10. (5pts) Provide the complete arrow pushing mechanism for the chemical transformation → depicted below Use proper curved arrow notation that explicitly illustrates all bonds being broken, and all bonds formed in the transformation. Also, be sure to include all lone pairs and formal charges on all atoms involved in the flow of electrons. CH3O II HA H CH3O-H H ①arrow_forward
- Do the Lone Pairs get added bc its valence e's are a total of 6 for oxygen and that completes it or due to other reasons. How do we know the particular indication of such.arrow_forwardNGLISH b) Identify the bonds present in the molecule drawn (s) above. (break) State the function of the following equipments found in laboratory. Omka) a) Gas mask b) Fire extinguisher c) Safety glasses 4. 60cm³ of oxygen gas diffused through a porous hole in 50 seconds. How long w 80cm³ of sulphur(IV) oxide to diffuse through the same hole under the same conditions (S-32.0.0-16.0) (3 m 5. In an experiment, a piece of magnesium ribbon was cleaned with steel w clean magnesium ribbon was placed in a crucible and completely burnt in oxy cooling the product weighed 4.0g a) Explain why it is necessary to clean magnesium ribbon. Masterclass Holiday assignmen PB 2arrow_forwardHi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning