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(a)
Interpretation:
The number of moles of hydrogen gas evolved needs to be determined when 1.385 g of an unknown metal is reacted with an excess of HCl to evolve the gas with a volume of 382.6 mL at 20.0°C and 755 mmHg pressure.
Concept introduction:
Solution stoichiometry involves the calculation of the concentration of solutions in the given conditions of volumes, moles, etc. There are various ways to calculate the concentration of solutions such as molarity, molality, mole fraction, ppm, ppb etc. Mole fraction is the ratio of moles of substance and total moles in the solution or mixture. One ppm stands for part per million or milligrams per liter (mg/L) whereas parts per billion (ppb) is one part in 1 billion.
Molarity represents the moles of solute dissolved in per liter of solution. The mathematical expression of molarity is:
(b)
Interpretation:
The mass of
Concept introduction:
From the number of moles and molar mass, the mass of substance can be calculated as follows:
Here, n is number of moles and M is molar mass.
(c)
Interpretation:
The molality of particles of
Concept introduction:
Molality represents the moles of solute dissolve in per kg of solvent. The mathematical expression of molality is:
From freezing point depression, the molality can be determined using the following relation:
(d)
Interpretation:
The number of moles of ions present in solution of
Concept introduction:
Solution stoichiometry involves the calculation of the concentration of solutions in the given conditions of volumes, moles, etc. There are various ways to calculate the concentration of solutions such as molarity, molality, mole fraction, ppm, ppb etc. Mole fraction is the ratio of moles of substance and total moles in the solution or mixture. One ppm stands for part per million or milligrams per liter (mg/L) whereas parts per billion (ppb) is one part in 1 billion.
Molarity represents the moles of solute dissolved in per liter of solution. The mathematical expression of molarity is:
(e)
Interpretation:
The formula and molecular weight of
Concept introduction:
Solution stoichiometry involves the calculation of the concentration of solutions in the given conditions of volumes, moles, etc. There are various ways to calculate the concentration of solutions such as molarity, molality, mole fraction, ppm, ppb etc. Mole fraction is the ratio of moles of substance and total moles in the solution or mixture. One ppm stands for part per million or milligrams per liter (mg/L) whereas parts per billion (ppb) is one part in 1 billion.
Molarity represents the moles of solute dissolved in per liter of solution. The mathematical expression of molarity is:
(f)
Interpretation:
The metal M in
Concept introduction:
Solution stoichiometry involves the calculation of the concentration of solutions in the given conditions of volumes, moles, etc. There are various ways to calculate the concentration of solutions such as molarity, molality, mole fraction, ppm, ppb etc. Mole fraction is the ratio of moles of substance and total moles in the solution or mixture. One ppm stands for part per million or milligrams per liter (mg/L) whereas parts per billion (ppb) is one part in 1 billion.
Molarity represents the moles of solute dissolved in per liter of solution. The mathematical expression of molarity is:
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Chapter 13 Solutions
CHEMISTRY-TEXT
- IV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forward
- Nonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forward
- given cler asnwerarrow_forwardAdd curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Draw curved arrows. : 0: si H : OH :: H―0: Harrow_forwardConsider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑arrow_forward
- Macroscale and Microscale Organic ExperimentsChemistryISBN:9781305577190Author:Kenneth L. Williamson, Katherine M. MastersPublisher:Brooks Cole
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