(a) To Determine: The respective lines of solution in graph. Calculation: T f = K f I m As, solution B having the greater value of I = 3 , which indicates that its change in boiling temperature is higher than solution A. T 0 f -T f = T f s With larger value of change in freezing temperature, the temperature of solutionwill be lower of red line. From graph, blue line having the higher freezing temperature considered as solution A whereas Solution B havethe lower temperature present with red line. For A, T f s = 14 C 0 For B, T f s = 11 C 0
(a) To Determine: The respective lines of solution in graph. Calculation: T f = K f I m As, solution B having the greater value of I = 3 , which indicates that its change in boiling temperature is higher than solution A. T 0 f -T f = T f s With larger value of change in freezing temperature, the temperature of solutionwill be lower of red line. From graph, blue line having the higher freezing temperature considered as solution A whereas Solution B havethe lower temperature present with red line. For A, T f s = 14 C 0 For B, T f s = 11 C 0
As, solution B having the greater value of I = 3 , which indicates that its change in boiling temperature is higher than solution A. T0f -Tf= Tfs
With larger value of change in freezing temperature, the temperature of solutionwill be lower of red line.
From graph, blue line having the higher freezing temperature considered as solution A whereas Solution B havethe lower temperature present with red line.
For A, Tfs = 14 C0 For B, Tfs = 11 C0
Interpretation Introduction
(b)
To Determine:
Melting temperature of pure solvent A and B
Calculation:
As, both the solutions having the same concentration So, considering the concentrations, m1 = m2 = 1 m
Freezing point of pure solvent is also considered as the melting point.
T0f =Tfs + Tf For A, Tf = Kf I m = 3 * 1 * 1 = 3 C0. T0f = 14 + 3 = 17 C0.
For B, Tf = Kf I m = 3 * 3* 1 = 9 C0. T0f = 11 + 9 = 20 C0.
Thus, for pure solvent A and B, the melting temperature are 17 C and 20 C
2. Draw the missing structure(s) in each of the following reactions. The missing
structure(s) can be a starting material or the major reaction product(s).
Ph
H-I
CH2Cl2
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Draw the products formed in the following oxidative cleavage.
[1] 03
[2] H₂O
draw structure ...
lower mass
product
draw structure ...
higher mass
product
2. Draw the missing structure(s) in each of the following reactions. The missing
structure(s) can be a starting material or the major reaction product(s).
H-Br
CH2Cl2
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