ORGANIC CHEM +SG +SAPLING >IP<
6th Edition
ISBN: 9781319171179
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 13, Problem 13.11P
Interpretation Introduction
Interpretation:
The
Concept introduction:
Nuclear magnetic resonance is a type of spectroscopy in which number of different kind of protons present in different environment can be detected. Chemical shift is defined as the distance from the reference point. Protons present in different environment gives different absoprtion peak in
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In the drawing area below, draw the major products of this organic reaction:
If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area
instead.
1. NaH
2. CH3Br
?
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structure.
No reaction.
: ☐
N
+
Predict the major product of the following reaction.
: ☐
+
☑
ค
OH
H₂SO4
Click and drag to start
drawing a structure.
Consider this organic reaction:
...
OH
CI
Draw the major products of the reaction in the drawing area below. If there won't be any major products, because this reaction won't happen at a significant
rate, check the box under the drawing area instead.
☐ No Reaction.
Click and drag to start drawing a structure.
:
а
Chapter 13 Solutions
ORGANIC CHEM +SG +SAPLING >IP<
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.24PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27PCh. 13 - Prob. 13.28PCh. 13 - Prob. 13.29PCh. 13 - Prob. 13.30PCh. 13 - Prob. 13.31PCh. 13 - Prob. 13.32PCh. 13 - Prob. 13.33PCh. 13 - Prob. 13.34PCh. 13 - Prob. 13.35PCh. 13 - Prob. 13.36APCh. 13 - Prob. 13.37APCh. 13 - Prob. 13.38APCh. 13 - Prob. 13.39APCh. 13 - Prob. 13.40APCh. 13 - Prob. 13.41APCh. 13 - Prob. 13.42APCh. 13 - Prob. 13.43APCh. 13 - Prob. 13.44APCh. 13 - Prob. 13.45APCh. 13 - Prob. 13.46APCh. 13 - Prob. 13.47APCh. 13 - Prob. 13.48APCh. 13 - Prob. 13.49APCh. 13 - Prob. 13.50APCh. 13 - Prob. 13.51APCh. 13 - Prob. 13.52APCh. 13 - Prob. 13.53APCh. 13 - Prob. 13.54APCh. 13 - Prob. 13.55APCh. 13 - Prob. 13.56APCh. 13 - Prob. 13.57APCh. 13 - Prob. 13.58APCh. 13 - Prob. 13.59APCh. 13 - Prob. 13.60APCh. 13 - Prob. 13.61APCh. 13 - Prob. 13.62APCh. 13 - Prob. 13.63APCh. 13 - Prob. 13.64APCh. 13 - Prob. 13.65APCh. 13 - Prob. 13.67AP
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- 32. Consider a two-state system in which the low energy level is 300 J mol 1 and the higher energy level is 800 J mol 1, and the temperature is 300 K. Find the population of each level. Hint: Pay attention to your units. A. What is the partition function for this system? B. What are the populations of each level? Now instead, consider a system with energy levels of 0 J mol C. Now what is the partition function? D. And what are the populations of the two levels? E. Finally, repeat the second calculation at 500 K. and 500 J mol 1 at 300 K. F. What do you notice about the populations as you increase the temperature? At what temperature would you expect the states to have equal populations?arrow_forward30. We will derive the forms of the molecular partition functions for atoms and molecules shortly in class, but the partition function that describes the translational and rotational motion of a homonuclear diatomic molecule is given by Itrans (V,T) = = 2πmkBT h² V grot (T) 4π²IKBT h² Where h is Planck's constant and I is molecular moment of inertia. The overall partition function is qmolec Qtrans qrot. Find the energy, enthalpy, entropy, and Helmholtz free energy for the translational and rotational modes of 1 mole of oxygen molecules and 1 mole of iodine molecules at 50 K and at 300 K and with a volume of 1 m³. Here is some useful data: Moment of inertia: I2 I 7.46 x 10- 45 kg m² 2 O2 I 1.91 x 101 -46 kg m²arrow_forwardK for each reaction step. Be sure to account for all bond-breaking and bond-making steps. HI HaC Drawing Arrows! H3C OCH3 H 4 59°F Mostly sunny H CH3 HO O CH3 'C' CH3 Select to Add Arrows CH3 1 L H&C. OCH3 H H H H Select to Add Arrows Q Search Problem 30 of 20 H. H3C + :0: H CH3 CH3 20 H2C Undo Reset Done DELLarrow_forward
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