Chapter 13, Problem 115SAE

Interpretation Introduction

(a)

Interpretation:

The normal boiling point of cyclopentane needs to be estimated.

Concept introduction:

The standard entropy and standard enthalpy of vaporization is related to boiling point with formula:

$\text{ΔSvap ° = }\frac{\text{ΔHvap °}}{\text{Tb}}$

Interpretation Introduction

(b)

Interpretation:

The value of $\text{ΔrG°}$ for the vaporization of cyclopentane at 298 K needs to be estimated.

Concept introduction:

The value of $\text{ΔrG}°$ for a chemical reaction can be calculate with the help of standard $\text{ΔrG}°$ values of reactant and product molecules. It can also calculate with the help of Gibb’s equation.

$\begin{array}{l}\text{ΔrG° = ΔrG°(product) - ΔrG°(reactant) }\\ \\ \text{ΔrG° = ΔrH° - TΔrS° }\end{array}$

Interpretation Introduction

(c)

Interpretation:

The significance of the sign of $\text{ΔrG°}$ for the vaporization of cyclopentane at 298 K needs to be determined.

Concept introduction:

The value of $\text{ΔrG}°$ for a chemical reaction can be calculate with the help of standard $\text{ΔrG}°$ values of reactant and product molecules. It can also calculate with the help of Gibb’s equation.

$\begin{array}{l}\text{ΔrG° = ΔrG°(product) - ΔrG°(reactant) }\\ \\ \text{ΔrG° = ΔrH° - TΔrS° }\end{array}$