Chapter 12.8, Problem 10PPS

To determine

Find the ratio of the surface area of the small pyramid to the surface area of the large pyramid.

Answer to Problem 10PPS

1:4

Explanation of Solution

Given:

Two similar pyramids have slant heights of 6 inches and 12 inches .

Formula Used: If the ratio of the sides of two similar solids is a : b , then the ratio of the surface area of the solids is

  $a^2:b^2$

Calculation:

Given:

Ratio of slant height of the smaller pyramid to the slant height of the larger pyramid:

  $\frac{6}{12}=\frac{1}{2}$

= 1:2

So, the ratio of the surface area of the small pyramid to the surface area of the large pyramid is $1^2:2^2=1:4$