Chapter 12, Problem 6MCQ

To determine

To calculate : The lateral area of the cable.

Answer to Problem 6MCQ

The lateral area of the cable would be $L=392.5fee{t}^2$

Explanation of Solution

Given information : The circular cable with diameter $3$ inches and height as $500$ feet given.

Formula used : The lateral area of the cylinder is $L=\pi dh$ . Where $d$ is the diameter and $h$ is the height of the cylinder. Also, $1$ feet $=12$ inches.

Calculation : Convert the given diameter in feet.

  $3$ inches $=\frac{3}{12}=0.25$ feet.

Now, calculate the lateral area.

  $L=\pi dh$

  $\begin{array}{l}L=\pi \times 0.25\times 500\\ L=392.5fee{t}^2\end{array}$