Chapter 12.7, Problem 7MRE

To determine

To determine the equation of each figure described.

Answer to Problem 7MRE

  $x^2+y^2+2x-8y-8=0$

Explanation of Solution

Given information :

Circle with center (-1, 4) and radius 3.

Equation of circle is given by,

  ${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$

Where $h$ and $k$ are center and $r$ is radius.

Hence the equation of given data becomes,

  $\begin{array}{l}{\left(x-\left(-1\right)\right)}^2+{\left(y-4\right)}^2=3^2\\ x^2+1+2x+y^2+16-8y=9\\ x^2+y^2+2x-8y-8=0\end{array}$