Chapter 12.6, Problem 1RC

Interpretation Introduction

Interpretation:

The heat of vaporization at each of the two given slopes have to be found out.

Concept Introduction:

In the plot of $\text{ln}\text{P}$ versus $\text{1/T}$ , the slope is $\frac{{\text{-ΔH}}_{\text{vap}}}{\text{R}}$ .

Here,

$\begin{array}{l}\text{P}\text{=}\text{Vapor}\text{pressure}\text{.}\\ \text{T}\text{=}\text{Temperature}\text{.}\end{array}$

$\begin{array}{c}{\text{ΔH}}_{\text{vap}}=\text{Heat}\text{of}\text{vaporization}\text{. }\\ \text{R}\text{=}\text{Gas}\text{constant}\text{=8}\text{.314}\text{J/K}\text{.mol}\end{array}$

${\text{ΔH}}_{\text{vap}}=\text{Heat}\text{of}\text{vaporization}$ is the amount of heat energy required to vaporize one mole of a substance.