Recursion: A technique where an algorithm is described in terms of itself is called as recursion. a) Code: //class definition class Main { //method definition public static int mystery5(int x,int y) { //condition to validate the value of x if (x<0) { //return value return -mystery5(-x,y); } //else part else if(y<0) { //return value return -mystery5(x,-y); } //else part else if(x==0 && y==0) {

Question

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Answer 1

Expert Solution & Answer

Chapter 12.3, Problem 14SCP

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

a)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

b)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

c)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

...

Explanation of Solution

d)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Explanation of Solution

e)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Expert Solution & Answer

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Check out a sample textbook solution

See solution

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PLEG136: Week 5 Portofolio Project Motion to Compel

B A E H Figure 1 K Questions 1. List the shortest paths between all node pairs. Indicate the number of shortest paths that pass through each edge. Explain how this information helps determine edge betweenness. 2. Compute the edge betweenness for each configuration of DFS. 3. Remove the edge(s) with the highest betweenness and redraw the graph. Recompute the edge betweenness centrality for the new graph. Explain how the network structure changes after removing the edge. 4. Iteratively remove edges until at least two communities form. Provide step-by-step calculations for each removal. Explain how edge betweenness changes dynamically during the process. 5. How many communities do you detect in the final step? Compare the detected communities with the original graph structure. Discuss whether the Girvan- Newman algorithm successfully captures meaningful subgroups. 6. If you were to use degree centrality instead of edge betweenness for community detection, how would the results change?

Unit 1 Assignment 1 – Loops and Methods (25 points) Task: You are working for Kean University and given the task of building an Email Registration System. Your objective is to generate a Kean email ID and temporary password for every new user. The system will prompt for user information and generate corresponding credentials. You will develop a complete Java program that consists of the following modules: Instructions: 1. Main Method: ○ The main method should include a loop (of your choice) that asks for input from five users. For each user, you will prompt for their first name and last name and generate the email and password by calling two separate methods. Example о Enter your first name: Joe Enter your last name: Rowling 2.generateEmail() Method: This method will take the user's first and last name as parameters and return the corresponding Kean University email address. The format of the email is: • First letter of the first name (lowercase) + Full last name (lowercase) +…

Answer 2

Expert Solution & Answer

Chapter 12.3, Problem 14SCP

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

a)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

b)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

c)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

...

Explanation of Solution

d)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Explanation of Solution

e)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 12.3, Problem 14SCP

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

a)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

b)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

c)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

...

Explanation of Solution

d)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Explanation of Solution

e)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 12.3, Problem 14SCP

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

a)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

b)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

c)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

...

Explanation of Solution

d)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Explanation of Solution

e)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 12.3, Problem 14SCP

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

a)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

b)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Explanation of Solution

c)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

...

Explanation of Solution

d)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Explanation of Solution

e)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Answer 8

Chapter 12.3, Problem 14SCP

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

a)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Answer 9

Chapter 12.3, Problem 14SCP

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

a)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Answer 10

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

b)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Answer 11

Explanation of Solution

Recursion:

A technique where an algorithm is described in terms of itself is called as recursion.

b)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

Answer 12

Explanation of Solution

c)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

...

Answer 13

Explanation of Solution

c)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

...

Answer 14

Explanation of Solution

d)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Answer 15

Explanation of Solution

d)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Answer 16

Explanation of Solution

e)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Answer 17

Explanation of Solution

e)

Code:

//class definition

class Main

{

//method definition

public static int mystery5(int x,int y)

{

//condition to validate the value of x

if (x<0)

{

//return value

return -mystery5(-x,y);

}

//else part

else if(y<0)

{

//return value

return -mystery5(x,-y);

}

//else part

else if(x==0 && y==0)

{

//return value

return 0;

}

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 21

Ch. 12.1 - What is recursion? How does a recursive method...Ch. 12.1 - Prob. 2SCP Ch. 12.1 - Prob. 3SCP Ch. 12.1 - Prob. 4SCP Ch. 12.1 - Prob. 5SCP Ch. 12.1 - Prob. 6SCP Ch. 12.1 - Prob. 7SCP Ch. 12.2 - Prob. 8SCP Ch. 12.2 - What would be the effect if the code for the...Ch. 12.2 - What would be the effect if the code for the...

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Chapter 12 Solutions