Program code: // class definition class Main { //main method public static void main(String[] args) { //loop that iterates for the values for(int i=0;i<=4;i++) //display the starstring System.out.println(starString(i)); } //method definition public static String starString(int n) { //condition to validate the value passed if (n < 0) { //throw illegal argument exception throw new IllegalArgumentException(); } //else part for value 0 else if (n == 0) { //return * return ""; } //else part else { //return the string return starString(n - 1) + starString(n - 1); } } } Explanation: The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition. If the value of n is less than 0 then illegal argument exception is passed. If the value of n is equal to 0 then the “” is returned. If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Question

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Answer 1

Expert Solution & Answer

Chapter 12, Problem 1E

Explanation of Solution

Program code:

// class definition

class Main

{

  //main method

  public static void main(String[] args)

  {

    //loop that iterates for the values

    for(int i=0;i<=4;i++)

    //display the starstring

    System.out.println(starString(i));

  }

  //method definition

  public static String starString(int n)

  {

    //condition to validate the value passed

    if (n < 0)

    {

        //throw illegal argument exception

        throw new IllegalArgumentException();

    }

    //else part for value 0

    else if (n == 0)

    {

        //return *

        return "";

    }

    //else part

    else

    {

        //return the string

        return starString(n - 1) + starString(n - 1);

    }

}

}

Explanation:

The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition.

If the value of n is less than 0 then illegal argument exception is passed.

If the value of n is equal to 0 then the “” is returned.

If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Expert Solution & Answer

Sample Output

Output

*

**

****

********

****************

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After playing our giving implementation, your task is to implement Dinning Philosophers with semaphore in C, by including and Your implementation will require creating five philosophers, each identified by a number 0.4. Each philosopher will run as a separate thread. Create threads using Pthreads as discussed in the Lecture slides on Chapter 4 and Practice Lab on Threads. Your solution needs to accomplish the following: Implement in C (15 points) 1. dp1.c - You are to provide your solution to this assignment as a single C program named 'dp1.c using semaphore. Explain in you code (as comments) that the dead lock will happen or not. If there is a possible deadlock, you can simply solve the deadlock by pick the fork in order like the first solution in our slides. Solve Deadlock by Footman (15 points) 1. Here is a new solution to overcome the deadlock. The Dining Philosophers decide to hire a footman whose task to allow only four philosophers to sit on the table. When entering and…

8.4 Self-Bias Configuration 20. Determine Zi. Zo. and A,, for the network of Fig. 8.73 if gf, = 3000 μS and gos = 50 μs. 21. Determine Z, Zo, and A, for the network of Fig. 8.73 if the 20-uF capacitor is removed and the parameters of the network are the same as in Problem 20. Compare results with those of Problem 20. +12 V 3.3 ΚΩ HE C₂ Vo Z Zo C₁ 10 ΜΩ Z₁ 1.1 ΚΩ Cs 20 µF FIG. 8.73 Problems 20, 21, 22, and 59.

21. Determine Zi, Zo, and A, for the network of Fig. 8.73 if the 20-μF capacitor is removed and the parameters of the network are the same as in Problem 20. Compare results with those of Problem 20. +12 V 3.3 ΚΩ +6 C₂ C₁ Z₁ 10 ΜΩ 1.1 ΚΩ Cs 20 μF FIG. 8.73 Zo

Answer 2

Expert Solution & Answer

Chapter 12, Problem 1E

Explanation of Solution

Program code:

// class definition

class Main

{

  //main method

  public static void main(String[] args)

  {

    //loop that iterates for the values

    for(int i=0;i<=4;i++)

    //display the starstring

    System.out.println(starString(i));

  }

  //method definition

  public static String starString(int n)

  {

    //condition to validate the value passed

    if (n < 0)

    {

        //throw illegal argument exception

        throw new IllegalArgumentException();

    }

    //else part for value 0

    else if (n == 0)

    {

        //return *

        return "";

    }

    //else part

    else

    {

        //return the string

        return starString(n - 1) + starString(n - 1);

    }

}

}

Explanation:

The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition.

If the value of n is less than 0 then illegal argument exception is passed.

If the value of n is equal to 0 then the “” is returned.

If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Expert Solution & Answer

Sample Output

Output

*

**

****

********

****************

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Answer 3

Expert Solution & Answer

Chapter 12, Problem 1E

Explanation of Solution

Program code:

// class definition

class Main

{

  //main method

  public static void main(String[] args)

  {

    //loop that iterates for the values

    for(int i=0;i<=4;i++)

    //display the starstring

    System.out.println(starString(i));

  }

  //method definition

  public static String starString(int n)

  {

    //condition to validate the value passed

    if (n < 0)

    {

        //throw illegal argument exception

        throw new IllegalArgumentException();

    }

    //else part for value 0

    else if (n == 0)

    {

        //return *

        return "";

    }

    //else part

    else

    {

        //return the string

        return starString(n - 1) + starString(n - 1);

    }

}

}

Explanation:

The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition.

If the value of n is less than 0 then illegal argument exception is passed.

If the value of n is equal to 0 then the “” is returned.

If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Expert Solution & Answer

Sample Output

Output

*

**

****

********

****************

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Expert Solution & Answer

Chapter 12, Problem 1E

Explanation of Solution

Program code:

// class definition

class Main

{

  //main method

  public static void main(String[] args)

  {

    //loop that iterates for the values

    for(int i=0;i<=4;i++)

    //display the starstring

    System.out.println(starString(i));

  }

  //method definition

  public static String starString(int n)

  {

    //condition to validate the value passed

    if (n < 0)

    {

        //throw illegal argument exception

        throw new IllegalArgumentException();

    }

    //else part for value 0

    else if (n == 0)

    {

        //return *

        return "";

    }

    //else part

    else

    {

        //return the string

        return starString(n - 1) + starString(n - 1);

    }

}

}

Explanation:

The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition.

If the value of n is less than 0 then illegal argument exception is passed.

If the value of n is equal to 0 then the “” is returned.

If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Expert Solution & Answer

Sample Output

Output

*

**

****

********

****************

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 12, Problem 1E

Explanation of Solution

Program code:

// class definition

class Main

{

  //main method

  public static void main(String[] args)

  {

    //loop that iterates for the values

    for(int i=0;i<=4;i++)

    //display the starstring

    System.out.println(starString(i));

  }

  //method definition

  public static String starString(int n)

  {

    //condition to validate the value passed

    if (n < 0)

    {

        //throw illegal argument exception

        throw new IllegalArgumentException();

    }

    //else part for value 0

    else if (n == 0)

    {

        //return *

        return "";

    }

    //else part

    else

    {

        //return the string

        return starString(n - 1) + starString(n - 1);

    }

}

}

Explanation:

The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition.

If the value of n is less than 0 then illegal argument exception is passed.

If the value of n is equal to 0 then the “” is returned.

If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Expert Solution & Answer

Sample Output

Output

*

**

****

********

****************

Answer 8

Chapter 12, Problem 1E

Explanation of Solution

Program code:

// class definition

class Main

{

  //main method

  public static void main(String[] args)

  {

    //loop that iterates for the values

    for(int i=0;i<=4;i++)

    //display the starstring

    System.out.println(starString(i));

  }

  //method definition

  public static String starString(int n)

  {

    //condition to validate the value passed

    if (n < 0)

    {

        //throw illegal argument exception

        throw new IllegalArgumentException();

    }

    //else part for value 0

    else if (n == 0)

    {

        //return *

        return "";

    }

    //else part

    else

    {

        //return the string

        return starString(n - 1) + starString(n - 1);

    }

}

}

Explanation:

The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition.

If the value of n is less than 0 then illegal argument exception is passed.

If the value of n is equal to 0 then the “” is returned.

If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Expert Solution & Answer

Sample Output

Output

*

**

****

********

****************

Answer 9

Chapter 12, Problem 1E

Explanation of Solution

Program code:

// class definition

class Main

{

  //main method

  public static void main(String[] args)

  {

    //loop that iterates for the values

    for(int i=0;i<=4;i++)

    //display the starstring

    System.out.println(starString(i));

  }

  //method definition

  public static String starString(int n)

  {

    //condition to validate the value passed

    if (n < 0)

    {

        //throw illegal argument exception

        throw new IllegalArgumentException();

    }

    //else part for value 0

    else if (n == 0)

    {

        //return *

        return "";

    }

    //else part

    else

    {

        //return the string

        return starString(n - 1) + starString(n - 1);

    }

}

}

Explanation:

The method “starString” is used to print the star to the console and it made by validating the value of n using “if” condition.

If the value of n is less than 0 then illegal argument exception is passed.

If the value of n is equal to 0 then the “” is returned.

If the value is greater than 0 then recursively the function “starString” is executed to print the string.

Answer 10

Expert Solution & Answer

Sample Output

Output

*

**

****

********

****************

Answer 11

Expert Solution & Answer

Answer 12

Expert Solution & Answer

Answer 13

Ch. 12.1 - What is recursion? How does a recursive method...Ch. 12.1 - Prob. 2SCP Ch. 12.1 - Prob. 3SCP Ch. 12.1 - Prob. 4SCP Ch. 12.1 - Prob. 5SCP Ch. 12.1 - Prob. 6SCP Ch. 12.1 - Prob. 7SCP Ch. 12.2 - Prob. 8SCP Ch. 12.2 - What would be the effect if the code for the...Ch. 12.2 - What would be the effect if the code for the...

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