To determine To construct: An extended frequency distribution for the set of numbers and calculate the mean for the grouped data. Explanation Given: The data of frequency distribution is given as follows: ( 1.52 , 1.68 , 1.46 , 1.13 , 1.89 , 1.44 , 1.56 , 1.09 , 1.81 , 1.79 , 1.23 , 1.46 , 1.91 , 1.40 , 1.30 , 1.35 , 1.79 , 1.61 , 1.80 , 1.26 , 1.29 , 1.40 , 1.57 , 1.53 , 1.28 , 1.45 , 1.72 , 1.35 , 1.93 , 1.86 , 1.95 , 1.70 , 1.88 , 1.76 and 1.05 ) Procedure used: “Steps for constructing the frequency distribution: 1. Defined the classes using the class width. 2. For each of the class place the tally marks, if the data value is in the class interval. 3. Count the number of tally marks for each class interval for obtaining frequency. Steps for finding mean of grouped data: 1. Calculate the midpoint by finding the mean of the endpoints of the class. This is denoted by M . 2. Multiply the each of the frequency F with the corresponding midpoint M for each of the class. These values are denoted as ‘Product, FM ’. 3. Calculate the sum of the frequencies which is denoted as n . 4. Calculate the sum of ‘Product, FM ’. 5. Divide the sum of ‘Product, FM ’ with the sum n .” Calculation: Note that, all the class intervals are defined with the width of 0.09. Place the tally marks for each of the data value within the interval and count all the tally marks for frequency of each class. The frequency distribution is, Class Tally Frequency, F 1.00–1.09 | | 2 1.10–1.19 | 1 1.20–1.29 | | | | 4 1.30–1.39 | | | 3 1.40–1.49 | | | | | 6 1.50–1.59 | | | | 4 1

Mathematics for the Trades: A Guided Approach (10th Edition) - Standalone book

10th Edition

ISBN: 9780133347777

Author: Robert A. Carman Emeritus, Hal M. Saunders

Publisher: PEARSON

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Chapter 12.2, Problem 1BE

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To construct: An extended frequency distribution for the set of numbers and calculate the mean for the grouped data.

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Chapter 12.2, Problem 8AE

Chapter 12.2, Problem 2BE

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1. 2. Show that the following are not logically equivalent by finding a counterexample: (p^q) →r and (db) V (d←d) Show that the following is not a contradiction by finding a counterexample: (pV-q) AqA (pv¬q Vr) 3. Here is a purported proof that (pq) ^ (q → p) = F: (db) v (bd) = (db) v (bd) =(qVp) A (g→p) = (¬¬q V ¬p) ^ (q→ p) (db) V (db) = =¬(a→p)^(a→p) = (gp) ^¬(a → p) =F (a) Show that (pq) ^ (q→p) and F are not logically equivalent by finding a counterex- ample. (b) Identify the error(s) in this proof and justify why they are errors. Justify the other steps with their corresponding laws of propositional logic.

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Chapter 12 Solutions

Mathematics for the Trades: A Guided Approach (10th Edition) - Standalone book

Ch. 12.1 - A. Answer the questions following each...Ch. 12.1 - Trades Management The following graph shows the...Ch. 12.1 - Prob. 3AE Ch. 12.1 - Prob. 4AE Ch. 12.1 - Prob. 5AE Ch. 12.1 - Automotive Trades The following line graph shows...Ch. 12.1 - Prob. 7AE Ch. 12.1 - General Interest Study the circle graph at the top...Ch. 12.1 - Prob. 9AE Ch. 12.1 - Allied Health An assistant at a pharmaceutical...

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