Given the problem y" 6y+18y0 and a solution y₁ = e3* sin(3x) Applying the reduction of order method we obtain (you have to choose some nonzero numerical value for C) Y2(x) = Cy1u So the general solution to y" - 3y' + 4y = 0 can be written as y = = C131+C2J2 = C1 c +

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