Explanation Given Information: The marginal revenue for a month for a commodity is, M R ¯ = − 0.006 x + 36 . Formula used: The power rule of integrals, ∫ x n d x = x n + 1 n + 1 + C ( n ≠ 1 ) Calculation: As it is provided that the marginal revenue for a month for a commodity is, M R ¯ = − 0.006 x + 36 Now, the marginal revenue can be obtained by differentiating the total revenue function R ( x ) as, R ′ ( x ) = − 0.006 x + 36 Thus, the total revenue can be obtained by integrating the above function as, R ( x ) = ∫ ( − 0.006 x + 36 ) d x Now, integrate the above function using power rule of integrals as, R ( x ) = − 0.006 [ x 2 2 ] + 36 x + C = − 0

Mathematical Applications for the Management, Life, and Social Sciences

12th Edition

ISBN: 9781337625340

Author: Ronald J. Harshbarger, James J. Reynolds

Publisher: Cengage Learning

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Chapter 12.1, Problem 44E

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To calculate: The total revenue from the production and sale of 75 units if the marginal revenue for a month for a commodity is MR¯=−0.006x+36.

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Chapter 12.1, Problem 43E

Chapter 12.1, Problem 45E

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Chapter 12 Solutions

Mathematical Applications for the Management, Life, and Social Sciences

Ch. 12.1 - 1. True or false: (a) (b) Ch. 12.1 - Prob. 2CP Ch. 12.1 - 1. If what is Ch. 12.1 - Prob. 2E Ch. 12.1 - Prob. 3E Ch. 12.1 - Prob. 4E Ch. 12.1 - Prob. 5E Ch. 12.1 - Evaluate the integrals in Problems 5-28. Check...Ch. 12.1 - Prob. 7E Ch. 12.1 - Evaluate the integrals in Problems 5-28. Check...

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The total revenue from the production and sale of 75 units if the marginal revenue for a month for a commodity is M R ¯ = − 0.006 x + 36 .

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To calculate: The total revenue from the production and sale of 75 units if the marginal revenue for a month for a commodity is MR¯=−0.006x+36.

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Chapter 12 Solutions