Engineering Fundamentals: An Introduction to Engineering
Engineering Fundamentals: An Introduction to Engineering
6th Edition
ISBN: 9780357112311
Author: Saeed Moaveni
Publisher: Cengage Learning US
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Chapter 12.1, Problem 3BYG
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The pin-connected structure consists of a rigid beam ABCD and two supporting bars. Bar (1) is an aluminum alloy [E = 79 GPa] with a cross-sectional area of A₁ = 780 mm². Bar (2) is a bronze alloy [E = 104 GPa] with a cross-sectional area of A₂ = 460 mm². Assume L₁=1.6 m, L₂-2.1 m, a=0.6 m, b=1.8 m, and c-1.3 m. All bars are unstressed before the load P is applied; however, there is a 4-mm clearance in the pin connection at A. If a load of P = 58 kN is applied at B, determine: (a) the normal stresses 01,02, in both bars (1) and (2). (b) the normal strains €1,2, in bars (1) and (2). (c) determine the downward deflection VA of point A on the rigid bar. (1) L₁ B Answers: (a)σ = b ล L2 C D i MPa, σ1 = i MPa. με, Ε2 = i με. (b) €1 = i (C) VA = i mm.
Current Attempt in Progress A load of P 117 kN is supported by a structure consisting of rigid bar ABC, two identical solid bronze [E= 83 GPa] rods, and a solid steel [E 182 GPa] rod, as shown. The bronze rods (1) each have a diameter of 20 mm and they are symmetrically positioned relative to the center rod (2) and the applied load P. Steel rod (2) has a diameter of 26 mm. All bars are unstressed before the load Pis applied; however, there is a 3.4-mm clearance in the bolted connection at B. Assume L₁ = 3.3 m and L2 = 1.6 m. Determine: (a) the normal stresses in the bronze and steel rods (01, 02). (b) the downward deflection v of rigid bar ABC. (1) Answers: L2 (2) (1) B P (a) σ = (b) y = eTextbook and Media Save for Later MPa. MPa, 02 = mm. Attempts: 0 of 5 used Submit Answer
A vinyl [E= 2.60 GPa; v = 0.43] block with width b = 50 mm, depth d = 100 mm, and height h = 270 mm rests on a smooth rigid base. A load P is applied to a rigid plate that rests on top of the block. Calculate the change in the depth dimension d of the block after a load of P = 120 kN is applied. Rigid plate Answer: Ad= Width b Depth d Height Rigid base mm
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