(a) Explanation Given information: The weight ( W ) of the rocket is 0.2 lb. The thrust ( F t ) for first one second is 2 lb. The thrust ( F t ) 1 after the one second is 0. Calculation: Write the equation of mass ( m ) of the rocket: m = W g Here, g is the acceleration due to gravity. Sketch the free body diagram and kinetic diagram of the rocket as shown in Figure (1). Refer Figure (1), Consider the thrust phase ( 0 ≤ t ≤ 1 s ) . Apply Newton’s law of equation along vertical axis. Σ F = m a F t − W = m a Substitute W g for m . Σ F = m a F t − W = W g a a = g W ( F t − W ) a = g ( F t W − 1 ) Substitute 32.2 ft/s 2 for g , 2 lb for F t , and 0.2 lb for W . a = 32.2 ( 2 0.2 − 1 ) = 289.8 ft/s 2 Find the velocity ( v 1 ) of rocket at t = 1 s using the equation: v 1 = a t Substitute 289.8 ft/s 2 for a and 1 s for t . v 1 = ( 289.8 ) ( 1 ) = 289.8 ft/s Find the height ( y 1 ) traveled by the rocket at t = 1 s using the equation: y 1 = 1 2 a t 2 Substitute 289 (b) To determine The time required to reach this maximum height.

Connect 1 Semester Access Card for Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9781259639272

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 12.1, Problem 12.6P

(a)

To determine

Find the maximum height h reached by the rocket.

(b)

To determine

The time required to reach this maximum height.

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Chapter 12.1, Problem 12.5P

Chapter 12.1, Problem 12.7P

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