Flight navigation. The airspeed indicator on some aircraft is affected by the changes in atmospheric pressure at different altitudes. A pilot can estimate the true airspeed by observing the indicated airspeed and adding to it about 1.6 % for every 1,000 feet of altitude. (A) A pilot maintains a constant reading of 200 miles per hour on the airspeed indicator as the aircraft climbs from sea level to an altitude of 10,000 feet . Write a linear equation that expresses true airspeed T (in miles per hour) in terms of altitude A (in thousands of feet). (B) What would be the true airspeed of the aircraft at 6,500 feet?
Flight navigation. The airspeed indicator on some aircraft is affected by the changes in atmospheric pressure at different altitudes. A pilot can estimate the true airspeed by observing the indicated airspeed and adding to it about 1.6 % for every 1,000 feet of altitude. (A) A pilot maintains a constant reading of 200 miles per hour on the airspeed indicator as the aircraft climbs from sea level to an altitude of 10,000 feet . Write a linear equation that expresses true airspeed T (in miles per hour) in terms of altitude A (in thousands of feet). (B) What would be the true airspeed of the aircraft at 6,500 feet?
Solution Summary: The author calculates the linear equation that expresses airspeed in miles per hour in terms of altitude in thousands of feet.
Flight navigation. The airspeed indicator on some aircraft is affected by the changes in atmospheric pressure at different altitudes. A pilot can estimate the true airspeed by observing the indicated airspeed and adding to it about
1.6
%
for every
1,000 feet
of altitude.
(A) A pilot maintains a constant reading of 200 miles per hour on the airspeed indicator as
the aircraft climbs from sea level to an altitude of
10,000 feet
. Write a linear equation that
expresses true airspeed
T
(in miles per hour) in terms of altitude A (in thousands of feet).
(B) What would be the true airspeed of the aircraft at
6,500 feet?
Use Euler's summation formula to prove that, for x > 2,
Σ
log n
n3
=
A
log x
2x2
n≤x
where A is a constant.
-
1
+0
4x2
log x
x3
"
•
•
Let > be a potential for the vector field F = (−2 y³, −6 xy² − 4 z³, −12 yz² + 4 2). Then the value of
sin((-1.63, 2.06, 0.57) – (0,0,0)) is
-
0.336
-0.931
-0.587
0.440
0.902
0.607
-0.609
0.146
Chapter 1 Solutions
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Elementary Statistics: Picturing the World (7th Edition)
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