ORGANIC CHEMISTRY-PRINT COMPANION (LL)
ORGANIC CHEMISTRY-PRINT COMPANION (LL)
4th Edition
ISBN: 9781119659594
Author: Klein
Publisher: WILEY
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Chapter 12, Problem 68IP

(a)

Interpretation Introduction

Interpretation:

The formation of secondary alcohol using a two-carbon compound is to be determined.

Concept Introduction:

Secondary alcohol can be generated in many ways, one of the possible ways being the addition of a Grignard reagent with a two-carbon aldehyde, followed by hydrolysis of the intermediate molecule. Using acetaldehyde as the starting material, the product can be obtained.

(b)

Interpretation Introduction

Interpretation:

A plausible reaction for the formation of the secondary alcohol product has to be determined using a two-carbon starting material.

Concept Introduction:

Secondary alcohol can be generated in many ways, one of the possible ways being the addition of a Grignard reagent with a two-carbon aldehyde, followed by hydrolysis of the intermediate molecule. Using acetaldehyde as the starting material, the product can be obtained.

(c)

Interpretation Introduction

Interpretation:

The formation of four-carbon primary alcohol using a two-carbon compound is to be determined.

Concept Introduction:

Primary alcohol can be generated in many ways, one of the possible ways is a substitution reaction of an alkyl halide with a strong base such as NaOH . The addition of carbon fragments in the starting compound can be achieved by a reaction with an alkynide. Using these steps, the product can be obtained.

(d)

Interpretation Introduction

Interpretation:

A plausible reaction for the formation of the secondary alcohol product has to be determined using a two-carbon starting material.

Concept Introduction:

Secondary alcohol can be generated in many ways. One of the possible ways is the addition of a Grignard reagent with a four-carbon aldehyde, (which can be formed from a two-carbon compound by the addition of alkynide) followed by hydrolysis of the intermediate molecule. Using bromoethane as the starting material, the product can be obtained.

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When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 40 0 DEPT 135 T 200 160 120 80 40 0 Draw the unknown amide. Select Dow Templates More Frage
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