Give the total number of valence electrons in each of the following molecules. msp; a . N 2 O c . C 3 H 8 b . B 2 H 6 d . NC1 3

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Answer 1

Textbook Question

Chapter 12, Problem 57QAP

Give the total number of valence electrons in each of the following molecules.

msp; $a . N 2 O c . C 3 H 8 b . B 2 H 6 d . NC1 3$

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $N2O$ is $16$ .

Explanation of Solution

Total valence electrons in $N2O$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in O$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $O$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in O=25+16=16 valence electrons$

Thus the number of valence electrons in $N2O$ is $16$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $B2H6$ is $12$ .

Explanation of Solution

Total valence electrons in $B2H6$ is calculated as shown below.

$Total valence electrons=nValence electrons in B+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $B$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in B+nValence electrons in H=23+61=12 valence electrons$

Thus the number of valence electrons in $B2H6$ is $12$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $C3H8$ is $20$ .

Explanation of Solution

Total valence electrons in $C3H8$ is calculated as shown below.

$Total valence electrons=nValence electrons in C+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $C$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in C+nValence electrons in H=34+81=20 valence electrons$

Thus the number of valence electrons in $C3H8$ is $20$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $NCl3$ is $26$ .

Explanation of Solution

Total valence electrons in $NCl3$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $Cl$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl=15+37=26 valence electrons$

Thus the number of valence electrons in $NCl3$ is $26$ .

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Answer 2

Textbook Question

Chapter 12, Problem 57QAP

Give the total number of valence electrons in each of the following molecules.

msp; $a . N 2 O c . C 3 H 8 b . B 2 H 6 d . NC1 3$

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $N2O$ is $16$ .

Explanation of Solution

Total valence electrons in $N2O$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in O$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $O$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in O=25+16=16 valence electrons$

Thus the number of valence electrons in $N2O$ is $16$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $B2H6$ is $12$ .

Explanation of Solution

Total valence electrons in $B2H6$ is calculated as shown below.

$Total valence electrons=nValence electrons in B+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $B$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in B+nValence electrons in H=23+61=12 valence electrons$

Thus the number of valence electrons in $B2H6$ is $12$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $C3H8$ is $20$ .

Explanation of Solution

Total valence electrons in $C3H8$ is calculated as shown below.

$Total valence electrons=nValence electrons in C+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $C$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in C+nValence electrons in H=34+81=20 valence electrons$

Thus the number of valence electrons in $C3H8$ is $20$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $NCl3$ is $26$ .

Explanation of Solution

Total valence electrons in $NCl3$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $Cl$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl=15+37=26 valence electrons$

Thus the number of valence electrons in $NCl3$ is $26$ .

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Answer 3

Textbook Question

Chapter 12, Problem 57QAP

Give the total number of valence electrons in each of the following molecules.

msp; $a . N 2 O c . C 3 H 8 b . B 2 H 6 d . NC1 3$

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $N2O$ is $16$ .

Explanation of Solution

Total valence electrons in $N2O$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in O$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $O$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in O=25+16=16 valence electrons$

Thus the number of valence electrons in $N2O$ is $16$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $B2H6$ is $12$ .

Explanation of Solution

Total valence electrons in $B2H6$ is calculated as shown below.

$Total valence electrons=nValence electrons in B+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $B$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in B+nValence electrons in H=23+61=12 valence electrons$

Thus the number of valence electrons in $B2H6$ is $12$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $C3H8$ is $20$ .

Explanation of Solution

Total valence electrons in $C3H8$ is calculated as shown below.

$Total valence electrons=nValence electrons in C+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $C$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in C+nValence electrons in H=34+81=20 valence electrons$

Thus the number of valence electrons in $C3H8$ is $20$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $NCl3$ is $26$ .

Explanation of Solution

Total valence electrons in $NCl3$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $Cl$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl=15+37=26 valence electrons$

Thus the number of valence electrons in $NCl3$ is $26$ .

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Answer 4

Textbook Question

Chapter 12, Problem 57QAP

Give the total number of valence electrons in each of the following molecules.

msp; $a . N 2 O c . C 3 H 8 b . B 2 H 6 d . NC1 3$

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $N2O$ is $16$ .

Explanation of Solution

Total valence electrons in $N2O$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in O$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $O$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in O=25+16=16 valence electrons$

Thus the number of valence electrons in $N2O$ is $16$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $B2H6$ is $12$ .

Explanation of Solution

Total valence electrons in $B2H6$ is calculated as shown below.

$Total valence electrons=nValence electrons in B+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $B$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in B+nValence electrons in H=23+61=12 valence electrons$

Thus the number of valence electrons in $B2H6$ is $12$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $C3H8$ is $20$ .

Explanation of Solution

Total valence electrons in $C3H8$ is calculated as shown below.

$Total valence electrons=nValence electrons in C+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $C$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in C+nValence electrons in H=34+81=20 valence electrons$

Thus the number of valence electrons in $C3H8$ is $20$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $NCl3$ is $26$ .

Explanation of Solution

Total valence electrons in $NCl3$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $Cl$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl=15+37=26 valence electrons$

Thus the number of valence electrons in $NCl3$ is $26$ .

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $N2O$ is $16$ .

Explanation of Solution

Total valence electrons in $N2O$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in O$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $O$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in O=25+16=16 valence electrons$

Thus the number of valence electrons in $N2O$ is $16$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $B2H6$ is $12$ .

Explanation of Solution

Total valence electrons in $B2H6$ is calculated as shown below.

$Total valence electrons=nValence electrons in B+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $B$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in B+nValence electrons in H=23+61=12 valence electrons$

Thus the number of valence electrons in $B2H6$ is $12$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $C3H8$ is $20$ .

Explanation of Solution

Total valence electrons in $C3H8$ is calculated as shown below.

$Total valence electrons=nValence electrons in C+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $C$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in C+nValence electrons in H=34+81=20 valence electrons$

Thus the number of valence electrons in $C3H8$ is $20$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $NCl3$ is $26$ .

Explanation of Solution

Total valence electrons in $NCl3$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $Cl$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl=15+37=26 valence electrons$

Thus the number of valence electrons in $NCl3$ is $26$ .

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $N2O$ is $16$ .

Explanation of Solution

Total valence electrons in $N2O$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in O$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $O$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in O=25+16=16 valence electrons$

Thus the number of valence electrons in $N2O$ is $16$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer 13

Answer to Problem 57QAP

The number of valence electrons in $N2O$ is $16$ .

Answer 14

Explanation of Solution

Total valence electrons in $N2O$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in O$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $O$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in O=25+16=16 valence electrons$

Thus the number of valence electrons in $N2O$ is $16$ .

Answer 15

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $B2H6$ is $12$ .

Explanation of Solution

Total valence electrons in $B2H6$ is calculated as shown below.

$Total valence electrons=nValence electrons in B+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $B$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in B+nValence electrons in H=23+61=12 valence electrons$

Thus the number of valence electrons in $B2H6$ is $12$ .

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Interpretation Introduction

(b)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer 20

Answer to Problem 57QAP

The number of valence electrons in $B2H6$ is $12$ .

Answer 21

Explanation of Solution

Total valence electrons in $B2H6$ is calculated as shown below.

$Total valence electrons=nValence electrons in B+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $B$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in B+nValence electrons in H=23+61=12 valence electrons$

Thus the number of valence electrons in $B2H6$ is $12$ .

Answer 22

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $C3H8$ is $20$ .

Explanation of Solution

Total valence electrons in $C3H8$ is calculated as shown below.

$Total valence electrons=nValence electrons in C+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $C$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in C+nValence electrons in H=34+81=20 valence electrons$

Thus the number of valence electrons in $C3H8$ is $20$ .

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Interpretation Introduction

(c)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer 27

Answer to Problem 57QAP

The number of valence electrons in $C3H8$ is $20$ .

Answer 28

Explanation of Solution

Total valence electrons in $C3H8$ is calculated as shown below.

$Total valence electrons=nValence electrons in C+nValence electrons in H$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $C$ and $H$ in the above expression.

$Total valence electrons=nValence electrons in C+nValence electrons in H=34+81=20 valence electrons$

Thus the number of valence electrons in $C3H8$ is $20$ .

Answer 29

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$

Where,

$n$ is the number of atoms.

Answer to Problem 57QAP

The number of valence electrons in $NCl3$ is $26$ .

Explanation of Solution

Total valence electrons in $NCl3$ is calculated as shown below.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl$

Where,

$n$ is the number of atoms.

Substitute the values of $n$ , valence electrons of $N$ and $Cl$ in the above expression.

$Total valence electrons=nValence electrons in N+nValence electrons in Cl=15+37=26 valence electrons$

Thus the number of valence electrons in $NCl3$ is $26$ .

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Interpretation Introduction

(d)

Interpretation:

The number of valence electrons of the given compound is to be stated.

Concept Introduction:

The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electron configuration. The description of every electron that is moving freely in an orbital is given by the electron configuration of that atom.

The electrons that are present in the outermost shell of an atom are known as valence electrons. The outermost shell of an atom is known as valence shell. The valence electrons are more loosely held than the electrons which are closer to the nucleus. The formula for the calculation of number of valence electrons in a molecule is:

$Total valence electrons=nValence electrons in Atom1+nValence electrons in Atom2+.......+nValence electrons in Atomm$